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Convert Base64 string to an image file? [duplicate]

I am trying to convert my base64 image string to an image file. This is my Base64 string: 8 Answers ...
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Pretty-print a Map in Java

...intingMap(Map<K, V> map) { this.map = map; } public String toString() { StringBuilder sb = new StringBuilder(); Iterator<Entry<K, V>> iter = map.entrySet().iterator(); while (iter.hasNext()) { Entry<K, V> entry = iter.next(...
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Deserializing JSON data to C# using JSON.NET

... Use var rootObject = JsonConvert.DeserializeObject<RootObject>(string json); Create your classes on JSON 2 C# Json.NET documentation: Serializing and Deserializing JSON with Json.NET share | ...
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How to sort a HashMap in Java [duplicate]

...if you want to do it once you can sort the values of your HashMap: Map<String, Person> people = new HashMap<>(); Person jim = new Person("Jim", 25); Person scott = new Person("Scott", 28); Person anna = new Person("Anna", 23); people.put(jim.getName(), jim); people.put(scott.getName(),...
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Best way to format integer as string with leading zeros? [duplicate]

I need to add leading zeros to integer to make a string with defined quantity of digits ($cnt). What the best way to translate this simple function from PHP to Python: ...
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How can I get an http response body as a string in Java?

... Every library I can think of returns a stream. You could use IOUtils.toString() from Apache Commons IO to read an InputStream into a String in one method call. E.g.: URL url = new URL("http://www.example.com/"); URLConnection con = url.openConnection(); InputStream in = con.getInputStream(); St...
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c# datatable to csv

... opens fine in Excel, maybe your issue was the trailing comma .net = 3.5 StringBuilder sb = new StringBuilder(); string[] columnNames = dt.Columns.Cast<DataColumn>(). Select(column => column.ColumnName). ToArray(); sb.A...
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Difference between InvariantCulture and Ordinal string comparison

When comparing two strings in c# for equality, what is the difference between InvariantCulture and Ordinal comparison? 9 An...
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Get cookie by name

...=== 2) return parts.pop().split(';').shift(); } Walkthrough Splitting a string by token will produce either, an array with one string (same value), in case token does not exist in a string, or an array with two strings , in case token is found in a string . The first (left) element is string of...
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Warning: “format not a string literal and no format arguments”

...r userInfo]); Or, since you say errorMsgFormat is a format string with a single placeholder, are you trying to do this? NSLog(@"%@, %@", [NSString stringWithFormat:errorMsgFormat, error], [error userInfo]); ...