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What command opens Ruby's REPL?
What command opens Ruby's REPL?
2 Answers
2
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What's the difference between '$(this)' and 'this'?
...s going to be in the first element.
$("#myDiv")[0] === document.getElementById("myDiv");
And so on...
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How set the default repository
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Yeah, tonfa's right on both counts. You do it by editing a file and if you don't want to pop open an editor you could do it by shell redirect. There's no 'set' command.
– Ry4an Brase
Sep 27 '10 at 13:56
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SQL: How to get the count of each distinct value in a column?
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SELECT
category,
COUNT(*) AS `num`
FROM
posts
GROUP BY
category
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JSON.parse unexpected character error
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@Mathletics By all accounts JSON.parse does some security check. N.T.
– B.F.
Apr 15 '14 at 9:33
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Java: Getting a substring from a string starting after a particular character
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Finally something really handy, didn't know about this method. I hate to hassle with substring + indexof + 1 - 2 +3 whatsoever. This is much cleaner :)
– BAERUS
Feb 6 '18 at 8:05
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Removing the fragment identifier from AngularJS urls (# symbol)
... Because IE lt 10 doesn't support html5 history API which were enabled by setting up html5Mode(true). In IE you have to use # in routes.
– Maxim Grach
Feb 8 '13 at 16:50
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How to get a property value based on the name
...n addition other guys answer, its Easy to get property value of any object by use Extension method like:
public static class Helper
{
public static object GetPropertyValue(this object T, string PropName)
{
return T.GetType().GetProperty(PropName) == null ? null : T.G...
MySQL - How to select data by string length
...for CHAR_LENGTH() to get the number of characters in a string.
For multi-byte charsets LENGTH() will give you the number of bytes the string occupies, while CHAR_LENGTH() will return the number of characters.
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How do you add an action to a button programmatically in xcode
I know how to add an IBAction to a button by dragging from the interface builder, but I want to add the action programmatically to save time and to avoid switching back and forth constantly. The solution is probably really simple, but I just can't seem to find any answers when I search it. Thank you...