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How to automatically generate N “distinct” colors?
...tness or saturation, you can distribute the hues like so:
// assumes hue [0, 360), saturation [0, 100), lightness [0, 100)
for(i = 0; i < 360; i += 360 / num_colors) {
HSLColor c;
c.hue = i;
c.saturation = 90 + randf() * 10;
c.lightness = 50 + randf() * 10;
addColor(c);
}
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Position of least significant bit that is set
... position of the least significant bit that is set in an integer, e.g. for 0x0FF0 it would be 4.
22 Answers
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Get a filtered list of files in a directory
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400
import glob
jpgFilenamesList = glob.glob('145592*.jpg')
See glob in python documenttion
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Programmatically create a UIView with color gradient
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702
Objective-C:
UIView *view = [[UIView alloc] initWithFrame:CGRectMake(0, 0, 320, 50)];
CAGradie...
Creating a comma separated list from IList or IEnumerable
...ng"};
string joined = string.Join(",", strings);
Detail & Pre .Net 4.0 Solutions
IEnumerable<string> can be converted into a string array very easily with LINQ (.NET 3.5):
IEnumerable<string> strings = ...;
string[] array = strings.ToArray();
It's easy enough to write the equiv...
How to determine if a list of polygon points are in clockwise order?
...se. (The result is twice the enclosed area, with a +/- convention.)
point[0] = (5,0) edge[0]: (6-5)(4+0) = 4
point[1] = (6,4) edge[1]: (4-6)(5+4) = -18
point[2] = (4,5) edge[2]: (1-4)(5+5) = -30
point[3] = (1,5) edge[3]: (1-1)(0+5) = 0
point[4] = (1,0) edge[4]: (5-1)(0+0) = 0
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What is the difference between shallow copy, deepcopy and normal assignment operation?
...rint id(c) == id(d) # True - d is the same object as c
print id(c[0]) == id(d[0]) # True - d[0] is the same object as c[0]
Using a shallow copy:
d = copy.copy(c)
print id(c) == id(d) # False - d is now a new object
print id(c[0]) == id(d[0]) # True - d[0] is the same obje...
Ruby on Rails and Rake problems: uninitialized constant Rake::DSL
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A tweet from DHH earlier. Rake .9.0 breaks Rails and several other things, you need to:
gem "rake", "0.8.7"
in your Gemfile.
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Which is faster in Python: x**.5 or math.sqrt(x)?
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math.sqrt(x) is significantly faster than x**0.5.
import math
N = 1000000
%%timeit
for i in range(N):
z=i**.5
10 loops, best of 3: 156 ms per loop
%%timeit
for i in range(N):
z=math.sqrt(i)
10 loops, best of 3: 91.1 ms per loop
Using Python 3.6....
C++ new int[0] — will it allocate memory?
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answered Jul 6 '09 at 13:46
Faisal ValiFaisal Vali
28.6k88 gold badges3939 silver badges4444 bronze badges
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