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Best way to format integer as string with leading zeros? [duplicate]

... You can use the zfill() method to pad a string with zeros: In [3]: str(1).zfill(2) Out[3]: '01' share | improve this answer | follow | ...
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How do I convert a float number to a whole number in JavaScript?

...74099 900719925474099 900719925474099 value | 0 // 858993459 858993459 858993459 ~~value // 858993459 858993459 858993459 value >> 0 // 858993459 858993459 858993459 value >>> 0 ...
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What is the Python 3 equivalent of “python -m SimpleHTTPServer”

What is the Python 3 equivalent of python -m SimpleHTTPServer ? 5 Answers 5 ...
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Finding local IP addresses using Python's stdlib

... answered Oct 3 '08 at 12:06 Vinko VrsalovicVinko Vrsalovic 236k4747 gold badges312312 silver badges359359 bronze badges ...
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How to install a previous exact version of a NPM package?

... 1639 If you have to install an older version of a package, just specify it npm install <package&...
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What is a good regular expression to match a URL? [duplicate]

...[-a-zA-Z0-9()@:%_\+.~#?&//=]*) To try this out see http://regexr.com?37i6s, or for a version which is less restrictive http://regexr.com/3e6m0. Example JavaScript implementation: var expression = /[-a-zA-Z0-9@:%._\+~#=]{1,256}\.[a-zA-Z0-9()]{1,6}\b([-a-zA-Z0-9()@:%_\+.~#?&//=]*)?/gi;...
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Matplotlib different size subplots

... 390 Another way is to use the subplots function and pass the width ratio with gridspec_kw: import...
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How many double numbers are there between 0.0 and 1.0?

...), there will therefore be 2 to the 52th power different doubles (i.e., 4503599627370496 of them). For example, that's the number of distinct doubles between 0.5 included and 1.0 excluded, and exactly that many also lie between 1.0 included and 2.0 excluded, and so forth. Counting the doubles betw...
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How to catch integer(0)?

... answered Jun 23 '11 at 8:30 Gavin SimpsonGavin Simpson 152k2424 gold badges354354 silver badges415415 bronze badges ...
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Remove rows with duplicate indices (Pandas DataFrame and TimeSeries)

... I would suggest using the duplicated method on the Pandas Index itself: df3 = df3[~df3.index.duplicated(keep='first')] While all the other methods work, the currently accepted answer is by far the least performant for the provided example. Furthermore, while the groupby method is only slightly les...