大约有 800 项符合查询结果(耗时:0.0107秒) [XML]
Is there a way to make R beep/play a sound at the end of a script?
...ered Jul 1 '14 at 18:08
Rasmus BååthRasmus Bååth
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...
What is your preferred style for naming variables in R? [closed]
...ered Nov 16 '12 at 8:55
Rasmus BååthRasmus Bååth
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...
Detect 7 inch and 10 inch tablet programmatically
...gth of the hypotenuse (In this case, the size of the screen diagonal).
//a² + b² = c²
//The size of the diagonal in inches is equal to the square root of the height in inches squared plus the width in inches squared.
double diagonalInches = Math.sqrt(
(widthInches * widthInches)
+ (hei...
Add single element to array in numpy
...
for k in range(int(10e4)):
d.append(k)
f = np.array(d)
13.5 ms ± 277 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
Pre-allocating numpy array:
e = np.zeros((n,))
for k in range(n):
e[k] = k
9.92 ms ± 752 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
When the...
pypi UserWarning: Unknown distribution option: 'install_requires'
...ed Nov 28 '11 at 15:38
Fredrik HåårdFredrik Håård
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...
Delete rows from a pandas DataFrame based on a conditional expression involving len(string) giving K
...than raw column based filtration:-
%timeit df_new = df[(df.E>0)]
345 µs ± 10.5 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)
%timeit dft.drop(dft[dft.E < 0].index, inplace=True)
890 µs ± 94.9 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)
A column is basical...
Efficiently replace all accented characters in a string?
...
"à":"a",
"ả":"a",
"ȃ":"a",
"ā":"a",
"ą":"a",
"ᶏ":"a",
"ẚ":"a",
"å":"a",
"ǻ":"a",
"ḁ":"a",
"ⱥ":"a",
"ã":"a",
"ꜳ":"aa",
"æ":"ae",
"ǽ":"ae",
"ǣ":"ae",
"ꜵ":"ao",
"ꜷ":"au",
"ꜹ":"av",
"ꜻ":"av",
"ꜽ":"ay",
"ḃ":"b",
"ḅ":"b",
"ɓ":"b",
"ḇ":"b",
"ᵬ":"b",
"ᶀ":"b",
"ƀ"...
传感器组件 · App Inventor 2 中文网
...
X分量
返回 X 维度的加速度,以 SI 单位 (m/s²) 表示。
必须启用传感器才能返回有意义的值。
Y分量
返回 Y 维度的加速度,以 SI 单位 (m/s²) 表示。
必须启用传感器才能返回有意义的值。
Z分量
返...
Extract subset of key-value pairs from Python dictionary object?
...works in 2.7 too):
{k: bigdict[k] for k in ('l', 'm', 'n')}
Update: As Håvard S points out, I'm assuming that you know the keys are going to be in the dictionary - see his answer if you aren't able to make that assumption. Alternatively, as timbo points out in the comments, if you want a key tha...
Modifying a subset of rows in a pandas dataframe
...ings
%timeit df['b'] = np.where(df.a.values == 0, np.nan, df.b.values)
685 µs ± 6.4 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each)
%timeit df.loc[df['a'] == 0, 'b'] = np.nan
3.11 ms ± 17.2 µs per loop (mean ± std. dev. of 7 runs, 100 loops each)
Numpy's where is about 4x faster
...