大约有 800 项符合查询结果(耗时:0.0106秒) [XML]

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Numpy: find first index of value fast

...e(100000) %timeit index(arr, 5) # 1000000 loops, best of 3: 1.88 µs per loop %timeit find_first(5, arr) # 1000000 loops, best of 3: 1.7 µs per loop %timeit index(arr, 99999) # 10000 loops, best of 3: 118 µs per loop %timeit find_first(99999, arr) # 10000 loops, best of 3: 9...
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Is there a way to make R beep/play a sound at the end of a script?

...ered Jul 1 '14 at 18:08 Rasmus BååthRasmus Bååth 3,62222 gold badges2121 silver badges2525 bronze badges ...
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Remove rows with duplicate indices (Pandas DataFrame and TimeSeries)

...>> %timeit df3.groupby(df3.index).first() 1000 loops, best of 3: 580 µs per loop >>> %timeit df3[~df3.index.duplicated(keep='first')] 1000 loops, best of 3: 307 µs per loop Note that you can keep the last element by changing the keep argument to 'last'. It should also be noted tha...
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Approximate cost to access various caches and main memory?

... Mutex lock/unlock 100 ns Main memory (RAM) 2 000 ns (2µs) 1KB Zippy-compress Still some improvements, prediction for 2020 16 000 ns (16µs) SSD random read (olibre's note: should be less) 500 000 ns (½ms) Round trip in datacenter 2 000 000 ns (2ms) HDD random read (s...
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What is your preferred style for naming variables in R? [closed]

...ered Nov 16 '12 at 8:55 Rasmus BååthRasmus Bååth 3,62222 gold badges2121 silver badges2525 bronze badges ...
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Add single element to array in numpy

... for k in range(int(10e4)): d.append(k) f = np.array(d) 13.5 ms ± 277 µs per loop (mean ± std. dev. of 7 runs, 100 loops each) Pre-allocating numpy array: e = np.zeros((n,)) for k in range(n): e[k] = k 9.92 ms ± 752 µs per loop (mean ± std. dev. of 7 runs, 100 loops each) When the...
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pypi UserWarning: Unknown distribution option: 'install_requires'

...ed Nov 28 '11 at 15:38 Fredrik HåårdFredrik Håård 2,4622020 silver badges3232 bronze badges ...
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Delete rows from a pandas DataFrame based on a conditional expression involving len(string) giving K

...than raw column based filtration:- %timeit df_new = df[(df.E>0)] 345 µs ± 10.5 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each) %timeit dft.drop(dft[dft.E < 0].index, inplace=True) 890 µs ± 94.9 µs per loop (mean ± std. dev. of 7 runs, 1000 loops each) A column is basical...
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Efficiently replace all accented characters in a string?

... "à":"a", "ả":"a", "ȃ":"a", "ā":"a", "ą":"a", "ᶏ":"a", "ẚ":"a", "å":"a", "ǻ":"a", "ḁ":"a", "ⱥ":"a", "ã":"a", "ꜳ":"aa", "æ":"ae", "ǽ":"ae", "ǣ":"ae", "ꜵ":"ao", "ꜷ":"au", "ꜹ":"av", "ꜻ":"av", "ꜽ":"ay", "ḃ":"b", "ḅ":"b", "ɓ":"b", "ḇ":"b", "ᵬ":"b", "ᶀ":"b", "ƀ"...
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What IDE to use for Python? [closed]

...| |*very limited Gedit |Y |F |Y¹|Y | | | |Y |Y |Y | | |Y²| | | | |¹with plugin; ²sort of Idle |Y |F |Y | |Y | | |Y |Y | | | | | | | | | IntelliJ |Y |CF|Y |Y |Y |Y |Y |Y |Y |Y |Y |Y |Y |Y |Y |Y |Y | JEdit |Y |F | |Y | | | | |...