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Laravel 4 Eloquent Query Using WHERE with OR AND OR?
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Make use of Parameter Grouping (Laravel 4.2). For your example, it'd be something like this:
Model::where(function ($query) {
$query->where('a', '=', 1)
->orWhere('b', '=', 1);
})->where(function ($query) {
$query->where(...
How to trigger ngClick programmatically
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The syntax is the following:
function clickOnUpload() {
$timeout(function() {
angular.element('#myselector').triggerHandler('click');
});
};
// Using Angular Extend
angular.extend($scope, {
clickOnUpload: clickOnUpload
});
// OR Using s...
How to show the loading indicator in the top status bar
I have noticed that some apps like Safari and Mail show a loading indicator in the status bar (the bar at the very top of the phone) when they are accessing the network. Is there a way to do the same thing in SDK apps, or is this an Apple only thing?
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How to alter SQL in “Edit Top 200 Rows” in SSMS 2008
In SQL Server 2008 Management Studio, when I right click on a database table and choose " Select Top 100 Rows ", I can then e.g. easily add a "ORDER BY " statement to the SQL. That works fine .
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Define an 's src attribute in CSS [duplicate]
I need to define an 's src attribute in CSS. Is there a way to specify this attribute?
7 Answers
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How to create JSON string in JavaScript?
In a code something like this, I am trying to create JSON string just to play around. It's throwing error, but if I put all the name, age, married in one single line (line 2) it doesn't. Whats the problem?
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UIImagePickerController breaks status bar appearance
In my .plist file, I have " View controller-based status bar appearance " set to NO . But after UIImagePickerController , my app behaves as if the option is set to YES .
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Trigger change event using jquery
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Also after changing option i wanted to execute the change event function. w.r.t this. alert box should execute.
– kishanio
May 11 '12 at 8:27
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Unpacking array into separate variables in JavaScript
...n AFAIK:
var one = arr[0],
two = arr[1];
ES6 will allow destructuring assignment:
let [x, y] = ['foo', 'bar'];
console.log(x); // 'foo'
console.log(y); // 'bar'
Or, to stick to your initial example:
var arr = ['one', 'two'];
var [one, two] = arr;
You could also create a default value:...
Keyword not supported: “data source” initializing Entity Framework Context
I'm initializing Entity Framework Object context, and this gives me the keyword not supported error:
6 Answers
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