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Database design for a survey [closed]

...ents, multiple choice questions, and possibly questions that could contain more than one answer (i.e. check all that apply). ...
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PHP check whether property exists in object or class

...t have a middle name'; To show how this would look in an if statement for more clarity on how this is working. if($person->middleName ?? false) { echo $person->middleName; } else { echo 'Person does not have a middle name'; } Explanation The traditional PHP way to check for someth...
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Landscape printing from HTML

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Parse an HTML string with JS

...I'm concerned is upvoted as the top answer. The parse() solution below is more reusable and elegant. – Justin Mar 7 '19 at 17:36 ...
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How do you properly use namespaces in C++?

... I see your point, but I disagree because name collisions are (in my mind) more likely to come from precisely such small libraries. Most people are careful not to name classes/functions the same as those in STL. That said, I agree that using namespace X; should be avoided in header files if possible...
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How do I programmatically “restart” an Android app?

... @Qulin, Guys! You cant be serious! This example is more like direction than real life example. You have to modify this snippet with starting activity name, intent id, and exit mechanics whatever you with. Do not blindly copy paste it. – Oleg Koshkin ...
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How to delete files/subfolders in a specific directory at the command prompt in Windows

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How do you sort a dictionary by value?

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Why don't Java's +=, -=, *=, /= compound assignment operators require casting?

...he result using the contracted form. A typecast of the result is generally more accurate than a typecast of the problematic argument. No typecast would make the contraction useless when using incompatible types, as it would always cause the compiler to throw an error out. – The...
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How to check if element exists using a lambda expression?

... While the accepted answer is correct, I'll add a more elegant version (in my opinion): boolean idExists = tabPane.getTabs().stream() .map(Tab::getId) .anyMatch(idToCheck::equals); Don't neglect using Stream#map() which allows to flatten the data structure before ...