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Does a break statement break from a switch/select?

...ully illustrative example: loop: for { switch expr { case foo: if condA { doA() break // like 'goto A' } if condB { doB() break loop // li...
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How to click first link in list of items after upgrading to Capybara 2.0?

...ge.find("div.panel", text: /Proposals/) do within page.find('tr', text: /Foo/) do page.should have_xpath('td[3]', text: @today) end end share | improve this answer | ...
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Aligning UIToolBar items

...e: "A", style: UIBarButtonItemStyle.Plain, target: viewController, action: foo) let button2 = UIBarButtonItem(title: "B", style: UIBarButtonItemStyle.Plain, target: viewController, action: bar) let button3 = UIBarButtonItem(title: "C", style: UIBarButtonItemStyle.Plain, target: viewControlle...
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JavaScript replace/regex

...he regexp): "$TESTONE $TESTONE".replace( new RegExp("\\$TESTONE","gm"),"foo") Otherwise, it looks for the end of the line and 'TESTONE' (which it never finds). Personally, I'm not a big fan of building regexp's using strings for this reason. The level of escaping that's needed could lead you ...
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Difference between `mod` and `rem` in Haskell

...nswered May 4 '11 at 23:54 Fred FooFred Foo 317k6464 gold badges662662 silver badges785785 bronze badges ...
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Do you need break in switch when return is used?

...ion execution. Also, if all of your case statements are like this: case 'foo': $result = find_result(...); break; And after the switch statement you just have return $result, using return find_result(...); in each case will make your code much more readable. Lastly, don't forget to add th...
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How does one use rescue in Ruby without the begin and end block

... A method "def" can serve as a "begin" statement: def foo ... rescue ... end share | improve this answer | follow | ...
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How do you get the index of the current iteration of a foreach loop?

...e { public static void Main() { string[] values = new[] { "foo", "bar", "baz" }; values.ForEachWithIndex((item, idx) => Console.WriteLine("{0}: {1}", idx, item)); } } share | ...
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How do I show the value of a #define at compile-time?

...code using "BOOST_VERSION"? Perhaps something like "blah[BOOST_VERSION] = foo;" will tell you something like "string literal 1.2.1 cannot be used as an array address". It won't be a pretty error message, but at least it'll show you the relevant value. You can play around until you find a compile ...
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How to apply a function to two columns of Pandas dataframe

...like sending 2 columns and a constant into a function (i.e. col_1, col_2, 'foo'). import numpy as np import pandas as pd df = pd.DataFrame({'ID':['1','2','3'], 'col_1': [0,2,3], 'col_2':[1,4,5]}) mylist = ['a','b','c','d','e','f'] def get_sublist(sta,end): return mylist[sta:end+1] #df['col_3...