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How can I test that a value is “greater than or equal to” in Jasmine?
I want to confirm that a value is a decimal (or 0), so the number should be greater than or equal to zero and less than 1.
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Version of SQLite used in Android?
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UPDATE OCT 2016: Here is a link to the updated official docs which includes the main points in this answer: android.database.sqlite package-level javadoc
Using the emulators:
adb shell sqlite3 --version
UPDATE: Since SDK 29 (emulator...
Invoke a callback at the end of a transition
...milar to jQuery) using D3.js . What I need to do is to set the opacity to 0 using transition() .
9 Answers
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Wait for a process to finish
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+50
To wait for any process to finish
Linux:
tail --pid=$pid -f /dev/null
Darwin (requires that $pid has open files):
lsof -p $pid +r...
What is the status of JSR 305?
I have seen the question JSR305 vs. JSR308 (Java Type Anotations) - Which is going to be the standard? and I understand the difference between JSR 308 and JSR 305 .
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arrayfun can be significantly slower than an explicit loop in matlab. Why?
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101
You can get the idea by running other versions of your code. Consider explicitly writing out th...
Java Round up Any Number
... correct function to call. I'm guessing a is an int, which would make a / 100 perform integer arithmetic. Try Math.ceil(a / 100.0) instead.
int a = 142;
System.out.println(a / 100);
System.out.println(Math.ceil(a / 100));
System.out.println(a / 100.0);
System.out.println(Math.ceil(a / 100.0));
Syst...
Python speed testing - Time Difference - milliseconds
...e.datetime.now()
>>> c = b - a
>>> c
datetime.timedelta(0, 4, 316543)
>>> c.days
0
>>> c.seconds
4
>>> c.microseconds
316543
Be aware that c.microseconds only returns the microseconds portion of the timedelta! For timing purposes always use c.total_sec...
In Python, how do I read the exif data for an image?
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answered Jan 22 '11 at 0:21
paynepayne
12.3k44 gold badges3434 silver badges4444 bronze badges
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Convert number strings with commas in pandas DataFrame to float
...e step.
You need to set the locale first:
In [ 9]: import locale
In [10]: from locale import atof
In [11]: locale.setlocale(locale.LC_NUMERIC, '')
Out[11]: 'en_GB.UTF-8'
In [12]: df.applymap(atof)
Out[12]:
0 1
0 1200 4200.00
1 7000 -0.03
2 5 0.00
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