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Get filename and path from URI from mediastore
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Below API 19 use this code to get File Path from URI:
public String getRealPathFromURI(Context context, Uri contentUri) {
Cursor cursor = null;
try {
String[] proj = { MediaStore.Images.Media.DATA };
cursor = context.getContentResolver().query(contentUri, proj, null, null...
Remove multiple spaces and new lines inside of String
Suppose we have string like this:
9 Answers
9
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Enforcing spaces in string resources [duplicate]
In an Android string resource, how do I enforce a space?
3 Answers
3
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What does the 'u' symbol mean in front of string values? [duplicate]
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The 'u' in front of the string values means the string is a Unicode string. Unicode is a way to represent more characters than normal ASCII can manage. The fact that you're seeing the u means you're on Python 2 - strings are Unicode by default on Py...
How to avoid “too many parameters” problem in API design?
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Condensing all the strings into a string array only makes sense if they're all related. From the order of arguments, it looks like they're not all completely related.
– icktoofay
Jun 4 '11 at 21:16
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How do I convert a NSString into a std::string?
I have an NSString object and want to convert it into a std::string .
3 Answers
3
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Splitting a Java String by the pipe symbol using split(“|”)
...ing the OR operator. You need to escape that character using \ (written in String as "\\" since \ is also a metacharacter in String literals and require another \ to escape it).
You can also use
test.split(Pattern.quote("|"));
and let Pattern.quote create the escaped version of the regex repres...
How can I create a UILabel with strikethrough text?
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SWIFT 4 UPDATE CODE
let attributeString: NSMutableAttributedString = NSMutableAttributedString(string: "Your Text")
attributeString.addAttribute(NSAttributedString.Key.strikethroughStyle, value: 2, range: NSMakeRange(0, attributeString.length))
then:
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C#: Looping through lines of multiline string
What is a good way to loop through each line of a multiline string without using much more memory (for example without splitting it into an array)?
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How can I use “.” as the delimiter with String.split() in java [duplicate]
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String.split takes a regex, and '.' has a special meaning for regexes.
You (probably) want something like:
String[] words = line.split("\\.");
Some folks seem to be having trouble getting this to work, so here is some run...