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How do I install the yaml package for Python?
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Debian-based systems:
$ sudo aptitude install python-yaml
or newer for python3
$ sudo aptitude install python3-yaml
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Numeric for loop in Django templates
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Note that you'll get 0-based behavior (0, 1, ... n-1).
(Updated for Python3 compatibility)
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Downloading a picture via urllib and python
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Couldn't even get urllib to work in python3. Requests had no issues and it's already loaded! The much better choice I reckon.
– user3023715
Nov 3 '17 at 11:58
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serve current directory from command line
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I've never seen anything as compact as
python3 -m http.server
You can optionally add a port number to the end:
python3 -m http.server 9000
See https://docs.python.org/library/http.server.html
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CentOS 6.4下Squid代理服务器的安装与配置 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...息。
Squid是一个缓存Internet 数据的软件，其接收用户的下载申请，并自动处理所下载的数据。当一个用户想要下载一个主页时，可以向Squid 发出一个申请，要Squid 代替其进行下载，然后Squid 连接所申请网站并请求该主页，接着...
error: command 'gcc' failed with exit status 1 while installing eventlet
...through apt on ubuntu/debian with:
sudo apt-get install python-dev
for python3 use:
sudo apt-get install python3-dev
For eventlet you might also need the libevent libraries installed so if you get an error talking about that you can install libevent with:
sudo apt-get install libevent-dev
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Check if an apt-get package is installed and then install it if it's not on Linux
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echo $?
sudo apt remove -y "$pkg"
dpkg -s "$pkg"
echo $?
ls -l /usr/lib/python3/dist-packages/certbot/reporter.py
sudo apt remove --purge certbot
dpkg -s "$pkg"
echo $?
ls -l /usr/lib/python3/dist-packages/certbot/reporter.py
then:
the first two echo $? output 0, only the third one outputs 1...
How can I convert a dictionary into a list of tuples?
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items() returns a dict_keys view in python3. Wrap this call with a cast to a list "list()". See @SilentGhost's reply
– Erich
Jul 11 '17 at 22:37
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Conditional Replace Pandas
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yield error: /opt/anaconda3/envs/python35/lib/python3.5/site-packages/ipykernel_launcher.py:1: SettingWithCopyWarning: A value is trying to be set on a copy of a slice from a DataFrame See the caveats in the documentation: pandas.pydata.org/pandas-docs/sta...
Python String and Integer concatenation [duplicate]
...ng = "string"
>>> [string+`i` for i in range(11)]
Update as per Python3
You can use :
string = 'string'
for i in range(11):
string +=str(i)
print string
It will print string012345678910.
To get string0, string1 ..... string10 you can use this as @YOU suggested
>>> string = "...