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const char* concatenation

... answered Jan 3 '10 at 14:05 codaddictcodaddict 395k7777 gold badges473473 silver badges507507 bronze badges ...
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Cosine Similarity between 2 Number Lists

... 13 Answers 13 Active ...
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How to install pip for Python 3 on Mac OS X?

...Python 2.7 stock installed. But I do all my own personal Python stuff with 3.3. I just flushed my 3.3.2 install and installed the new 3.3.3. So I need to install pyserial again. I can do it the way I've done it before, which is: ...
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Useful code which uses reduce()? [closed]

...me a lot... Here's some cute usages: Flatten a list Goal: turn [[1, 2, 3], [4, 5], [6, 7, 8]] into [1, 2, 3, 4, 5, 6, 7, 8]. reduce(list.__add__, [[1, 2, 3], [4, 5], [6, 7, 8]], []) List of digits to a number Goal: turn [1, 2, 3, 4, 5, 6, 7, 8] into 12345678. Ugly, slow way: int("".join(ma...
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Initializing a member array in constructor initializer

...assignments in the body. This is what boost::array does. Does the C++03 standard say anything special about initializing aggregates (including arrays) in ctor initializers? Or the invalidness of the above code is a corollary of some other rules? A mem-initializer uses direct initialization. ...
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Using Python 3 in virtualenv

... the default version of Python (2.7). On one project, I need to use Python 3.4. 22 Answers ...
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How to calculate moving average using NumPy?

... 173 If you just want a straightforward non-weighted moving average, you can easily implement it with...
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With bash, how can I pipe standard error into another process?

... mmlb 74777 silver badges2323 bronze badges answered Mar 27 '12 at 11:28 ScotScot 1,73611 gold badge1111...
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Find intersection of two nested lists?

... If you want: c1 = [1, 6, 7, 10, 13, 28, 32, 41, 58, 63] c2 = [[13, 17, 18, 21, 32], [7, 11, 13, 14, 28], [1, 5, 6, 8, 15, 16]] c3 = [[13, 32], [7, 13, 28], [1,6]] Then here is your solution for Python 2: c3 = [filter(lambda x: x in c1, sublist) for sublis...
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How to generate random number with the specific length in python

Let say I need a 3 digit number, so it would be something like: 8 Answers 8 ...