大约有 40,000 项符合查询结果(耗时:0.0369秒) [XML]

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如何快速导入拓展?拓展市场可一键导入 - App Inventor 2 中文网 - 清泛IT...

常用的拓展都可以一键导入,可以搜索你想要的拓展。如果没有找到,可以反馈给我们,会持续更新的。
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求助!关于拓展模块NotificationStyle的demo运行时报错的问题 - App Invent...

我使用的是demo程序进行测试,拓展程序链接: https://www.fun123.cn/reference/extensions/NotificationStyle.html 结果无论点什么按键都会报错: edu.mit.appinventor.aicompanion3: Targeting S+ (version 31 and above) requires that one of FLAG_IMMUTABLE or FLAG_MUTABLE be...
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- App Inventor 2 中文网 - 清泛IT社区,为创新赋能!

同样的代码我测试过,一切正常,不会收到非预期的数据。 会不会有其他订阅通道干扰,你自己写一个最简单的 demo,干净的环境再测试一下。
https://bbs.tsingfun.com/thread-2383-1-1.html 

App Inventor 输入文本如何转成ASCII码? - App Inventor 2 中文网 - 清泛I...

Q:App Inventor 输入文本如何转成ASCII码? A:使用AsciiConversion 拓展可以轻松实现。 AsciiCode: 给出字符,返回它相应的 Ascii码。 用法示例:返回字符“A”的Ascii码,结果将是:65。
https://bbs.tsingfun.com/thread-2395-1-1.html 

文件管理模块 - App Inventor 2 中文网 - 清泛IT社区,为创新赋能!

appinventor2中数据存储的文件管理器模块,手机找不到根目录怎么办请提供详细的报错等截图!
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列表显示框 - App Inventor 2 中文网 - 清泛IT社区,为创新赋能!

列表显示框如何根据名称筛选列表的内容,就像搜索框输入名字那样,可以筛选特定的内容,但是需要搜出来的时候就是筛选过的
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使用App Inventor扩展实现多点触控:Rotation Detector · App Inventor 2 中文

...关于我们 发布日志 服务条款 教育 中文教程 中文社区 反馈 我要反馈 var _hmt = _hmt || []; (function() { var hm = document.createElement("script"); hm.src = "https://hm.baidu.com/hm.j...
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How do I make a reference to a figure in markdown using pandoc?

...ecify the width or height of the image this way. Is it possible to include PDFs that way? If not that would also be a downside, since it is preferable in the PDF as output case. – Zelphir Kaltstahl Sep 21 '16 at 20:26 ...
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Copying text with color from Notepad++

... The easiest way worked for me is: Print your contents from npp++ to pdf by using microsoft print to pdf tool ( It will retain all the formatting and color code in pdf). Open that pdf file by using Microsoft Word and it will ask you the confirmation for conversion to word, convert it. If you...
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Generate a random point within a circle (uniformly)

...linearly with r. In other words, the desired probability density function (PDF) grows linearly. Since a PDF should have an area equal to 1 and the maximum radius is 1, we have                  So we know how the desired density of our random values should look like. Now: How do we...