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Python loop that also accesses previous and next values
How can I iterate over a list of objects, accessing the previous, current, and next items? Like this C/C++ code, in Python?
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How do I make HttpURLConnection use a proxy?
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can we provide proxy username and proxy password through it.
– Xolve
Jul 4 '10 at 10:15
16
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How to run Rake tasks from within Rake tasks?
...y_invoked state, allowing the task to
then be executed again, dependencies and all:
Rake::Task["build"].reenable
Rake::Task["build"].invoke
Note that dependencies already invoked are not automatically re-executed unless they are re-enabled. In Rake >= 10.3.2, you can use the following to re-ena...
Tools for creating Class Diagrams [closed]
...odeler, not a drawing tool. Your diagrams are UML-compliant, generate code and can be exported as UML/XMI files. It's web-based and free so it matches your criteria.
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Creating a blocking Queue in .NET?
I have a scenario where I have multiple threads adding to a queue and multiple threads reading from the same queue. If the queue reaches a specific size all threads that are filling the queue will be blocked on add until an item is removed from the queue.
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ThreadStart with parameters
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What is myParamObject and myUrl?
– dialex
Mar 14 '12 at 17:26
3
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What is the meaning of symbol $ in jQuery?
What does the $ sign in jQuery stand for?
11 Answers
11
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Write a number with two decimal places SQL server
... takes three arguments(the number, the number total characters to display, and the number of decimal places to display
Select Str(12345.6789, 12, 3)
displays: ' 12345.679' ( 3 spaces, 5 digits 12345, a decimal point, and three decimal digits (679). - it rounds if it has to truncate, (unless...
C++ equivalent of Java's toString?
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In C++ you can overload operator<< for ostream and your custom class:
class A {
public:
int i;
};
std::ostream& operator<<(std::ostream &strm, const A &a) {
return strm << "A(" << a.i << ")";
}
This way you can output instances ...
Why are Python lambdas useful? [closed]
...se elements of the original list that are multiples of 3. This is shorter (and, one could argue, clearer) than
def filterfunc(x):
return x % 3 == 0
mult3 = filter(filterfunc, [1, 2, 3, 4, 5, 6, 7, 8, 9])
Of course, in this particular case, you could do the same thing as a list comprehension:
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