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Defining a function with multiple implicit arguments in Scala
... in one parameter list, and this list must be the last one.
def myfun(arg:String)(implicit p1: String, p2:Int)={}
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Is there any way to use a numeric type as an object key?
...e a numeric type as a key name in an object, it always gets converted to a string. Is there anyway to actually get it to store as a numeric? The normal typecasting does not seem to work.
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Split a string by a delimiter in python
How to split this string where __ is the delimiter
3 Answers
3
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How do I write a “tab” in Python?
... code:
f = open(filename, 'w')
f.write("hello\talex")
The \t inside the string is the escape sequence for the horizontal tabulation.
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How do I turn a python datetime into a string, with readable format date?
How do I turn that into a string?:
7 Answers
7
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What is dynamic programming? [closed]
...problem just became more manageable.
Dynamic programming is used a lot in string problems, such as the string edit problem. You solve a subset(s) of the problem and then use that information to solve the more difficult original problem.
With dynamic programming, you store your results in some sort...
When should I use the HashSet type?
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Here's a real example of where I use a HashSet<string>:
Part of my syntax highlighter for UnrealScript files is a new feature that highlights Doxygen-style comments. I need to be able to tell if a @ or \ command is valid to determine whether to show it in gray (valid)...
Java Reflection: How to get the name of a variable?
...For example, take this simple class:
class TestLocalVarNames {
public String aMethod(int arg) {
String local1 = "a string";
StringBuilder local2 = new StringBuilder();
return local2.append(local1).append(arg).toString();
}
}
After compiling with javac -g:vars TestL...
Java 8 List into Map
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Based on Collectors documentation it's as simple as:
Map<String, Choice> result =
choices.stream().collect(Collectors.toMap(Choice::getName,
Function.identity()));
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TypeError: sequence item 0: expected string, int found
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string.join connects elements inside list of strings, not ints.
Use this generator expression instead :
values = ','.join(str(v) for v in value_list)
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