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Javascript/jQuery: Set Values (Selection) in a multiple Select
... $("#strings option[value='" + e + "']").prop("selected", true);
});
Working Example http://jsfiddle.net/McddQ/1/
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Convert an array of primitive longs into a List of Longs
This may be a bit of an easy, headdesk sort of question, but my first attempt surprisingly completely failed to work. I wanted to take an array of primitive longs and turn it into a list, which I attempted to do like this:
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Python Nose Import Error
I can't seem to get the nose testing framework to recognize modules beneath my test script in the file structure. I've set up the simplest example that demonstrates the problem. I'll explain it below.
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Why can't I use float value as a template parameter?
... as a template parameter, the compiler cries for this code, while int works fine.
11 Answers
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Select objects based on value of variable in object using jq
... from this post on Processing JSON with jq, you can use the select(bool) like this:
$ jq '.[] | select(.location=="Stockholm")' json
{
"location": "Stockholm",
"name": "Walt"
}
{
"location": "Stockholm",
"name": "Donald"
}
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Does Ruby have a string.startswith(“abc”) built in method?
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Jörg W MittagJörg W Mittag
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The source was not found, but some or all event logs could not be searched
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EventLog.SourceExists enumerates through the subkeys of HKLM\SYSTEM\CurrentControlSet\services\eventlog to see if it contains a subkey with the specified name. If the user account under which the code is running does not have read access to a subkey that it attempts to ac...
How to use ng-repeat without an html element
...sson's answer.
Otherwise, how about putting the ng-repeat on tbody? (AFAIK, it is okay to have multiple <tbody>s in a single table.)
<tbody ng-repeat="row in array">
<tr ng-repeat="item in row">
<td>{{item}}</td>
</tr>
</tbody>
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Listview Scroll to the end of the list after updating the list
I would like to make sure that the list is scrolled all the way to the bottom, after I have updated the listview by using listAdapter, so that it displays the last element entered in the list. How can I do this ?
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What's the best way to inverse sort in scala?
...ng may be done by method sorted with an implicit Ordering, which you may make explicit, and Ordering has a reverse (not the list reverse below)
You can do
list.sorted(theOrdering.reverse)
If the ordering you want to reverse is the implicit ordering, you can get it by implicitly[Ordering[A]] (A t...