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How can I remove the decimal part from JavaScript number?
...n the meantime.
Another method of truncating the fractional portion with excellent platform support is by using a bitwise operator (.e.g |0). The side-effect of using a bitwise operator on a number is it will treat its operand as a signed 32bit integer, therefore removing the fractional component. ...
python capitalize first letter only
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@Jan-PhilipGehrcke that is an exercise for the reader. You can see in that case, s is never empty, it is always '123sa' :D
– Ali Afshar
Sep 13 '12 at 16:02
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Is there a better alternative than this to 'switch on type'?
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Scala @ operator
...e following, for instance:
val o: Option[Int] = Some(2)
You can easily extract the content:
o match {
case Some(x) => println(x)
case None =>
}
But what if you wanted not the content of Some, but the option itself? That would be accomplished with this:
o match {
case x @ Some(_) =...
How to calculate the angle between a line and the horizontal axis?
...to determine how to calculate the angle between a line and the horizontal axis?
9 Answers
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What is context in _.each(list, iterator, [context])?
I am new to underscore.js. What is the purpose of [context] in _.each() ? How should it be used?
5 Answers
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How to copy text from Emacs to another application on Linux
When I cut (kill) text in Emacs 22.1.1 (in its own window on X, in KDE, on Kubuntu), I can't paste (yank) it in any other application.
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Way to get number of digits in an int?
...See my benchmark unit test below(wich may be flawed too i am no benchmark expert). Over a large number of runs (100 000 000), the speed is 11s to 8s on my machine hardly twice as fast.
– Jean
Aug 20 '09 at 15:36
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Qt: can't find -lGL error
...he error and in libgl1-... is for OpenGL, a fundamental dependency of Qt 5.x. This is a common error for devs when setting up for Qt development -- but once they install the OpenGL development lib they never see it again.
– pixelgrease
Jun 4 '15 at 23:04
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How to overwrite the previous print to stdout in python?
...') character to return to the start of the line without advancing to the next line:
for x in range(10):
print '{0}\r'.format(x),
print
The comma at the end of the print statement tells it not to go to the next line. The last print statement advances to the next line so your prompt won't overwri...
