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bootstrap popover not showing on top of all elements
... edited May 28 '14 at 8:46
Vaidas
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answered Apr 12 '13 at 22:37
KyleKy...
Changing UIButton text
...ly obvious, but there are several states available for buttons. If you provide the 'wrong' one, you will not see the text change as desired.
I noticed that my button was not showing the text I added, using the methods shown here. Check this link to make sure you are providing the UIControlState tha...
How to make my font bold using css?
...aration font-weight: bold;.
I would advise you to read the CSS beginner guide at http://htmldog.com/guides/cssbeginner/ .
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Navigation bar show/hide
...an app with a navigation bar consisting of 2 bar buttons. I would like to hide and show this navigation bar when a user double taps the screen.
...
Why would you use an ivar?
...ficantly more at times).
Program Correctness
Since the subclasses can override any method, you may eventually see there is a semantic difference between writing to the interface versus managing your state appropriately. Direct access for program correctness is especially common in partially construc...
Getting name of the class from an instance
... var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled...
Copy files from one directory into an existing directory
...he current directory, not the directory itself. This method also includes hidden files and folders.
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AngularJS ng-repeat handle empty list case
..."!events.length">No events</li>
See example.
Or you can use ngHide
<li ng-hide="events.length">No events</li>
See example.
For object you can test Object.keys.
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How to convert a Drawable to a Bitmap?
...
URL url_value = new URL(name);
ImageView profile = (ImageView)v.findViewById(R.id.vdo_icon);
if (profile != null) {
Bitmap mIcon1 =
BitmapFactory.decodeStream(url_value.openConnection().getInputStream());
profile.setImageBitmap(mIcon1);
}
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Returning JSON from a PHP Script
... should use header() commands only in addition with output buffering to avoid "headers already sent" warnings
– Kevin
Jul 2 '14 at 16:51
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