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What's this =! operator? [duplicate]
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That's two operators, = and !, not one. It might be an obfuscated way of writing
a = !b;
if (a) {
// whatever
}
setting a to the logical inverse of b, and testing whether the result is true (or, equivalently, whether b was false).
Or it might be a mistyping...
How to search file text for a pattern and replace it with a given value
...file (or list of files) for a pattern and, if found, replace that pattern with a given value.
10 Answers
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Have a div cling to top of screen if scrolled down past it [duplicate]
...ve a div which, when my page is first loaded, is about 100px from the top (it holds some buttons etc. for the page).
4 Answ...
https URL with token parameter : how secure is it?
On our site, we provide to users a simulation based on their private information (given through a form). We would like to allow them to get back on their simulation results later, but without forcing them to create a login/password account.
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Difference between Pig and Hive? Why have both? [closed]
My background - 4 weeks old in the Hadoop world. Dabbled a bit in Hive, Pig and Hadoop using Cloudera's Hadoop VM. Have read Google's paper on Map-Reduce and GFS ( PDF link ).
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Check to see if a string is serialized?
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I'd say, try to unserialize it ;-)
Quoting the manual :
In case the passed string is not
unserializeable, FALSE is returned and
E_NOTICE is issued.
So, you have to check if the return value is false or not (with === or !==, to be sure not to ...
AutoLayout with hidden UIViews?
I feel like it's a fairly common paradigm to show/hide UIViews , most often UILabels , depending on business logic. My question is, what is the best way using AutoLayout to respond to hidden views as if their frame was 0x0. Here is an example of a dynamic list of 1-3 features.
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Pimpl idiom vs Pure virtual class interface
I was wondering what would make a programmer to choose either Pimpl idiom or pure virtual class and inheritance.
10 Answers...
Convert object string to JSON
...SON.stringify(eval("(" + str + ")"));
Note that when you eval an object literal, it has to be wrapped in parentheses, otherwise the braces are parsed as a block instead of an object.
I also agree with the comments under the question that it would be much better to just encode the object in valid ...
How do I determine whether an array contains a particular value in Java?
I have a String[] with values like so:
29 Answers
29
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