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C++ templates Turing-complete?
I'm told that the template system in C++ is Turing-complete at compile time. This is mentioned in this post and also on wikipedia .
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How do I use arrays in C++?
C++ inherited arrays from C where they are used virtually everywhere. C++ provides abstractions that are easier to use and less error-prone ( std::vector<T> since C++98 and std::array<T, n> since C++11 ), so the need for arrays does not arise quite as often as it does in C. However, ...
Default value to a parameter while passing by reference in C++
...arameter of a function while we are passing the parameter by reference. in C++
17 Answers
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In what cases do I use malloc and/or new?
I see in C++ there are multiple ways to allocate and free data and I understand that when you call malloc you should call free and when you use the new operator you should pair with delete and it is a mistake to mix the two (e.g. Calling free() on something that was created with the new ...
“X does not name a type” error in C++
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C++ compilers process their input once. Each class you use must have been defined first. You use MyMessageBox before you define it. In this case, you can simply swap the two class definitions.
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How can I see the assembly code for a C++ program?
How can I see the assembly code for a C++ program?
14 Answers
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C++ inheritance - inaccessible base?
...r : public Foo
{
// ...
}
The default inheritance type of a class in C++ is private, so any public and protected members from the base class are limited to private. struct inheritance on the other hand is public by default.
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Correct way to define C++ namespace methods in .cpp file
...ass::method () in the namespace ns1. I prefer version 3.
See Namespaces (C++). This is the best way to do this.
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C++: How to round a double to an int? [duplicate]
... - (x<0); // x is now 55.499999...
int y = (int)x; // truncated to 55
C++11 also introduces std::round, which likely uses a similar logic of adding 0.5 to |x| under the hood (see the link if interested) but is obviously more robust.
A follow up question might be why the float isn't stored as e...
Can I assume (bool)true == (int)1 for any C++ compiler?
Can I assume (bool)true == (int)1 for any C++ compiler ?
4 Answers
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