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Javascript seconds to minutes and seconds
...
To get the number of full minutes, divide the number of total seconds by 60 (60 seconds/minute):
var minutes = Math.floor(time / 60);
And to get the remaining seconds, multiply the full minutes with 60 and subtract from the total seconds:
var seconds = time - minutes * 60;
Now if you also wan...
Awk学习笔记 - 更多技术 - 清泛网 - 专注C/C++及内核技术
...达式元字符
8. POSIX字符集
9. 匹配操作符(~)
10. 比较表达式
11. 范围模板
12. 一个验证passwd文件有效性的例子
13. 几个实例
14. awk编程
14.1. 变量
14.2. BEGIN模块
14.3. END模块
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How to create NS_OPTIONS-style bitmask enumerations in Swift?
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Swift 3.0
Almost identical to Swift 2.0. OptionSetType was renamed to OptionSet and enums are written lower case by convention.
struct MyOptions : OptionSet {
let rawValue: Int
static let firstOption = MyOptions(rawValue:...
Finding quaternion representing the rotation from one vector to another
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answered Jul 23 '09 at 14:04
Polaris878Polaris878
31.6k3535 gold badges105105 silver badges139139 bronze badges
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How to change plot background color?
...an use set_facecolor:
ax.set_facecolor('xkcd:salmon')
ax.set_facecolor((1.0, 0.47, 0.42))
As a refresher for what colors can be:
matplotlib.colors
Matplotlib recognizes the following formats to specify a color:
an RGB or RGBA tuple of float values in [0, 1] (e.g., (0.1, 0.2, 0....
Divide a number by 3 without using *, /, +, -, % operators
... x = t;
}
return y;
}
int divideby3(int num)
{
int sum = 0;
while (num > 3) {
sum = add(num >> 2, sum);
num = add(num >> 2, num & 3);
}
if (num == 3)
sum = add(sum, 1);
return sum;
}
As Jim commented this works, because:...
How do I count the number of occurrences of a char in a String?
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answered Nov 29 '09 at 22:23
CowanCowan
34.8k1111 gold badges6363 silver badges6363 bronze badges
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Best way to test if a row exists in a MySQL table
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edited Sep 4 '19 at 19:20
SovietFrontier
1,5441010 silver badges2727 bronze badges
answered Nov 4 '09 ...
How do you convert a byte array to a hexadecimal string, and vice versa?
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1402
Either:
public static string ByteArrayToString(byte[] ba)
{
StringBuilder hex = new StringBu...
Compare two DataFrames and output their differences side-by-side
... rows are empty*:
In [21]: ne = (df1 != df2).any(1)
In [22]: ne
Out[22]:
0 False
1 True
2 True
dtype: bool
Then we can see which entries have changed:
In [23]: ne_stacked = (df1 != df2).stack()
In [24]: changed = ne_stacked[ne_stacked]
In [25]: changed.index.names = ['id', 'col']
...