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How would you do a “not in” query with LINQ?
I have two collections which have property Email in both collections. I need to get a list of the items in the first list where Email does not exist in the second list. With SQL I would just use "not in", but I do not know the equivalent in LINQ. How is that done?
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Stack smashing detected
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Stack Smashing here is actually caused due to a protection mechanism used by gcc to detect buffer overflow errors. For example in the following snippet:
#include <stdio.h>
void func()
{
char array[10];
gets(array);
}
int main(int argc,...
Create a table without a header in Markdown
... headers
multimarkdown
Maruku: A popular implementation in Ruby
byword: "All tables must begin with one or more rows of headers"
PHP Markdown Extra "second line contains a mandatory separator line between the headers and the content"
RDiscount Uses PHP Markdown Extra syntax.
GitHub Flavoured Markd...
android get real path by Uri.getPath()
I'm trying to get image from gallery.
7 Answers
7
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Can mustache iterate a top-level array?
... Kai CarverKai Carver
1,8842424 silver badges2323 bronze badges
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How do I merge a git tag onto a branch
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Is there a way to merge all tags at once?
– ComFreek
Aug 18 '19 at 12:22
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error LNK2019: 无法解析的外部符号_socket，该符号在函数 中被引用 - C/C+...
...PP文件include语句之后加上如下代码：
#pragma comment(lib,"ws2_32.lib")
LNK2019 socket
Get the real width and height of an image with JavaScript? (in Safari/Chrome)
...eady finished downloading. If the image is not cached or if this code is called before window.onload, a height/width of 0 might be returned. In any case, I've integrated FDisk's idea into the solution above.
– Xavi
Feb 10 '11 at 2:26
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Python non-greedy regexes
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You seek the all-powerful *?
From the docs, Greedy versus Non-Greedy
the non-greedy qualifiers *?, +?, ??, or {m,n}? [...] match as little
text as possible.
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How do you remove duplicates from a list whilst preserving order?
...n seen or seen_add(x))]
Why assign seen.add to seen_add instead of just calling seen.add? Python is a dynamic language, and resolving seen.add each iteration is more costly than resolving a local variable. seen.add could have changed between iterations, and the runtime isn't smart enough to rule t...