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How do I break out of a loop in Perl?
...nd assuming you were just feeding given some scalar variable... but why do all that work just to use a break, it is (very) bad form, not to mention (blah!)just saying, its "possible" just not a good idea & not what you may think it is
– osirisgothra
Sep 1 '...
Static link of shared library function in gcc
How can I link a shared library function statically in gcc?
6 Answers
6
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How to install JSTL? The absolute uri: http://java.sun.com/jstl/core cannot be resolved
... deployed with this application
That URI is for JSTL 1.0, but you're actually using JSTL 1.2 which uses URIs with an additional /jsp path (because JSTL, who invented EL expressions, was since version 1.1 integrated as part of JSP in order to share/reuse the EL logic in plain JSP too).
So, fix the...
Start ssh-agent on login
...a remote Git repo pulling from Bitbucket.com using an SSH alias. I can manually start the ssh-agent on my server but I have to do this every time I login via SSH.
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Counting the occurrences / frequency of array elements
...be faster than creating an associative array.
– quant_dev
Sep 29 '17 at 20:24
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show 1 more comment
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Which regular expression operator means 'Don't' match this character?
*, ?, + characters all mean match this character. Which character means 'don't' match this? Examples would help.
4 Answers...
sed or awk: delete n lines following a pattern
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how to delete all lines after the pattern is matched ? I am using sed -e '/<!--#content end--></div>/,$d' out.txt but it gives error saying : sed: -e expression #1, char 24: extra characters after command Thanks in advance.
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How would you count occurrences of a string (actually a char) within a string?
...nsion methods on the string class. I guess they figured devs wouldn't want all those extension methods to show up on the string class. Probably a wise decision.
– Judah Gabriel Himango
Feb 15 '09 at 23:27
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How to generate a random string in Ruby
...).chr }.join
I spend too much time golfing.
(0...50).map { ('a'..'z').to_a[rand(26)] }.join
And a last one that's even more confusing, but more flexible and wastes fewer cycles:
o = [('a'..'z'), ('A'..'Z')].map(&:to_a).flatten
string = (0...50).map { o[rand(o.length)] }.join
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Remove all special characters from a string in R?
How to remove all special characters from string in R and replace them with spaces ?
3 Answers
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