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How to remove element from an array in JavaScript?
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MySQL: What's the difference between float and double?
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edited Jan 29 '10 at 9:12
answered Jan 29 '10 at 9:04
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How to assign from a function which returns more than one value?
...ue then functionReturningTwoValues()[[1]] or functionReturningTwoValues()[[2]] would be sufficient.)
See the cited r-help thread for more examples.
(2) with If the intent is merely to combine the multiple values subsequently and the return values are named then a simple alternative is to use with...
How do I loop through a list by twos? [duplicate]
I want to loop through a Python list and process 2 list items at a time. Something like this in another language:
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Why use the params keyword?
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With params you can call your method like this:
addTwoEach(1, 2, 3, 4, 5);
Without params, you can’t.
Additionally, you can call the method with an array as a parameter in both cases:
addTwoEach(new int[] { 1, 2, 3, 4, 5 });
That is, params allows you to use a shortcut when call...
Why can't R's ifelse statements return vectors?
...st vectors, you will get longer results:
> ifelse(c(TRUE, FALSE), c(1, 2), c(3, 4))
[1] 1 4
So ifelse is intended for the specific purpose of testing a vector of booleans and returning a vector of the same length, filled with elements taken from the (vector) yes and no arguments.
It is a comm...
javascript i++ vs ++i [duplicate]
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The difference between i++ and ++i is the value of the expression.
The value i++ is the value...
How can I profile C++ code running on Linux?
... stack. If there is some code that is wasting some percentage of the time, 20% or 50% or whatever, that is the probability that you will catch it in the act on each sample. So, that is roughly the percentage of samples on which you will see it. There is no educated guesswork required. If you do have...
Sort hash by key, return hash in Ruby
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In Ruby 2.1 it is simple:
h.sort.to_h
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Numpy first occurrence of value greater than existing value
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207
This is a little faster (and looks nicer)
np.argmax(aa>5)
Since argmax will stop at the ...