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Static variables in member functions

... iammilindiammilind 60.2k2727 gold badges146146 silver badges282282 bronze badges ...
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Nested JSON objects - do I have to use arrays for everything?

... 204 You don't need to use arrays. JSON values can be arrays, objects, or primitives (numbers or st...
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Why does parseInt(1/0, 19) return 18?

... The result of 1/0 is Infinity. parseInt treats its first argument as a string which means first of all Infinity.toString() is called, producing the string "Infinity". So it works the same as if you asked it to convert "Infinity" in base 19 ...
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Hadoop “Unable to load native-hadoop library for your platform” warning

... 230 I assume you're running Hadoop on 64bit CentOS. The reason you saw that warning is the native Ha...
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How to loop through all but the last item of a list?

... answered May 27 '09 at 9:04 freespacefreespace 15.1k33 gold badges3434 silver badges5555 bronze badges ...
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round() for float in C++

...in cmath (according to http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2012/n3337.pdf) #include <cmath> #include <iostream> int main(int argc, char** argv) { std::cout << "round(0.5):\t" << round(0.5) << std::endl; std::cout << "round(-0.5):\t" << r...
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Accessing class variables from a list comprehension in the class definition

...owing will fail: class A: a = 42 b = list(a + i for i in range(10)) So, to summarize: you cannot access the class scope from functions, list comprehensions or generator expressions enclosed in that scope; they act as if that scope does not exist. In Python 2, list comprehensions were i...
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HTML5 Pre-resize images before uploading

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How do I convert an integer to binary in JavaScript?

... function dec2bin(dec){ return (dec >>> 0).toString(2); } dec2bin(1); // 1 dec2bin(-1); // 11111111111111111111111111111111 dec2bin(256); // 100000000 dec2bin(-256); // 11111111111111111111111100000000 You can use Number.toString(2) function, but it has ...
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How do you check whether a number is divisible by another number (Python)?

I need to test whether each number from 1 to 1000 is a multiple of 3 or a multiple of 5. The way I thought I'd do this would be to divide the number by 3, and if the result is an integer then it would be a multiple of 3. Same with 5. ...