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How do 20 questions AI algorithms work?
... each step. This way you can approximate binary search.
Wikipedia gives a more complete example:
http://en.wikipedia.org/wiki/Decision_tree_learning
And some general background:
http://en.wikipedia.org/wiki/Decision_tree
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How to import a class from default package
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Welcome to StackOverflow! Perhaps you can add more details, to explain better the most important parts of your answer. Have a read of How do I write a good answer? for more information. Also, once you get more reputation, you will be able to post this as a comment rather...
Auto-size dynamic text to fill fixed size container
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What does (function($) {})(jQuery); mean?
...ugins without actually knowing what it means. Can someone tell me a little more about these? Perhaps an explanation will come in handy someday when writing a framework :)
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Parse query string in JavaScript [duplicate]
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Easy, but not very fast if you need to get more than one query value. I think a better abstraction is to return a JS object with all the name value pairs from the query string
– Juan Mendes
Sep 4 '12 at 23:37
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Setting Short Value Java
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You are right on both. I should have been more clear that I'm talking about integer literals here, not about floating-point literals.
– Lauri
Feb 19 '10 at 8:55
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C# version of java's synchronized keyword?
...in older Microsoft compilers it is a lock(this) / lock(Type) - however, in more recent compilers it uses Interlocked updates - so thread-safe without the nasty parts.
This allows more granular usage, and allows use of Monitor.Wait/Monitor.Pulse etc to communicate between threads.
A related blog en...
Eclipse java debugging: source not found
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hi thanks for all but i found this answer more usefull (stack over flow link)[stackoverflow.com/questions/5815013/…
– shareef
Aug 8 '12 at 12:16
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When would you call java's thread.run() instead of thread.start()?
... practice to use a separate Runnable object, though, since that leaves you more flexibility (such as passing it to an Executor, etc.).
– Adam Crume
Feb 27 '11 at 17:27
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A monad is just a monoid in the category of endofunctors, what's the problem?
...mulation of a monoid, × means the cartesian product of sets. You can read more about that here: en.wikipedia.org/wiki/Cartesian_product, but the basic idea is that an element of S × T is a pair (s, t), where s ∈ S and t ∈ T. So the signature of the monoidal product • : S × S -> S in this...