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Knight's Shortest Path on Chessboard
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You have a graph here, where all available moves are connected (value=1), and unavailable moves are disconnected (value=0), the sparse matrix would be like:
(a1,b3)=1,
(a1,c2)=1,
.....
And the shortest path of two points in a graph can be found usin...
How to generate random number with the specific length in python
... use an arbitrary number of digits:
from random import randint
def random_with_N_digits(n):
range_start = 10**(n-1)
range_end = (10**n)-1
return randint(range_start, range_end)
print random_with_N_digits(2)
print random_with_N_digits(3)
print random_with_N_digits(4)
Output:
33
124
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The difference between fork(), vfork(), exec() and clone()
...d I expected there to be a huge amount of information on this, but there really wasn't any solid comparison between the four calls.
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Select random row from a sqlite table
... the day seeded with unix epoc for today at noon so it shows the same book all day even if the query is run multiple times. Yes I know caching is more efficient for this use case just an example.
– danielson317
Apr 22 at 17:18
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How do I get Gridview to render THEAD?
...during postback and placed the code in the databound event which addressed all scenarios.
– James Westgate
Jun 10 '15 at 8:12
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Is there a way to perform “if” in python's lambda
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If you still want to print you can import future module
from __future__ import print_function
f = lambda x: print(x) if x%2 == 0 else False
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OnNotify函数 ON_NOTIFY消息总结 - C/C++ - 清泛网 - 专注C/C++及内核技术
OnNotify函数 ON_NOTIFY消息总结函数CWnd::OnNotify处理通知消息。其默认实现是检查通知消息处理函数的消息映射,然后调用。(checks the message map for notificatio...函数CWnd::OnNotify处理通知消息。其默认实现是检查通知消息处理函数的消息...
Unique constraint on multiple columns
...ied from technet's documentation, is in the form of:
CONSTRAINT constraint_name UNIQUE [ CLUSTERED | NONCLUSTERED ]
(
column [ ASC | DESC ] [ ,...n ]
)
Therefore, the resuting table definition would be:
CREATE TABLE [dbo].[user](
[userID] [int] IDENTITY(1,1) NOT NULL,
[fcode] [int] ...
Time complexity of Sieve of Eratosthenes algorithm
...oose upper-bound is n(1+1/2+1/3+1/4+1/5+1/6+…1/n) (sum of reciprocals of all numbers up to n), which is O(n log n): see Harmonic number. A more proper upper-bound is n(1/2 + 1/3 + 1/5 + 1/7 + …), that is sum of reciprocals of primes up to n, which is O(n log log n). (See here or here.)
The "find...
What's the simplest way to test whether a number is a power of 2 in C++?
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so basically (n>0 && ((n & (n-1)) == 0))
– Saurabh Goyal
Jul 10 '16 at 8:06
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