大约有 41,000 项符合查询结果（耗时：0.0305秒） [XML]
Why is argc not a constant?
...at any C function can do. Also, getopt is declared as int getopt(int argc, char * const argv[], const char *optstring);. And here the const is not top level, but declares the pointers to be const, a promise to not modify them (although the strings that they point to might conceivably be modified).
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Simple C example of doing an HTTP POST and consuming the response
...lude <netdb.h> /* struct hostent, gethostbyname */
void error(const char *msg) { perror(msg); exit(0); }
int main(int argc,char *argv[])
{
/* first what are we going to send and where are we going to send it? */
int portno = 80;
char *host = "api.somesite.com";
...
Why are Oracle table/column/index names limited to 30 characters?
...ine of code that goes something like
l_table_name VARCHAR2(30);
BEGIN
SELECT table_name
INTO l_table_name
FROM dba_tables
WHERE ...
to suddenly break because the DBA 15 years ago used VARCHAR2(30) rather than DBA_TABLES.TABLE_NAME%TYPE in the script would cause massive revolt. I w...
How to get the number of characters in a std::string?
How should I get the number of characters in a string in C++?
12 Answers
12
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Stripping out non-numeric characters in string
Hey Im looking to strip out non-numeric characters in a string in ASP.NET C#
11 Answers
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Detecting endianness programmatically in a C++ program
... for !
bool is_big_endian(void)
{
union {
uint32_t i;
char c[4];
} bint = {0x01020304};
return bint.c[0] == 1;
}
The principle is equivalent to the type case as suggested by others, but this is clearer - and according to C99, is guaranteed to be correct. gcc prefers ...
How to check if a String is numeric in Java
...
Note that the . in your regex will match any character, not just the decimal separator character.
– jqno
Jul 11 '09 at 8:16
9
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Does Notepad++ show all hidden characters?
...ould identify the character, where cursor takes 2 arrow keys
to move, just select that character.
do Ctrl-F
now you can count or
replace or even mark all such characters
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How to split a string in Haskell?
...n of words is,
words :: String -> [String]
words s = case dropWhile Char.isSpace s of
"" -> []
s' -> w : words s''
where (w, s'') = break Char.isSpace s'
So, change it for a function that takes a predicate:
words...
Is it possible to declare two variables of different types in a for loop?
...ound (not that i'd actually use it unless forced to):
for(struct { int a; char b; } s = { 0, 'a' } ; s.a < 5 ; ++s.a)
{
std::cout << s.a << " " << s.b << std::endl;
}
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