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Square retrofit server mock for testing
...ercept method and in the case if application is in DEBUG mode return given JSON.
RestClient.java
public final class RestClient {
private static IRestService mRestService = null;
public static IRestService getClient() {
if(mRestService == null) {
final OkHttpClient cl...
How to send a custom http status message in node / express?
...
You can use it like this
return res.status(400).json({'error':'User already exists.'});
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How can I pass data from Flask to JavaScript in a template?
...tation for more.
Also, have a look at Ford's answer who points out the tojson filter which is an addition to Jinja2's standard set of filters.
Edit Nov 2018: tojson is now included in Jinja2's standard set of filters.
sh...
Ensuring json keys are lowercase in .NET
Is there simple way using JSON in .NET to ensure that the keys are sent as lower case?
5 Answers
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Using GZIP compression with Spring Boot/MVC/JavaConfig with RESTful
...d=true
# opt in to content types
server.compression.mime-types=application/json,application/xml,text/html,text/xml,text/plain,application/javascript,text/css
# not worth the CPU cycles at some point, probably
server.compression.min-response-size=10240
In application.properties 1.2.2 - <1.3
se...
Angular ng-repeat Error “Duplicates in a repeater are not allowed.”
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For those who expect JSON and still getting the same error, make sure that you parse your data:
$scope.customers = JSON.parse(data)
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How to pass an array within a query string?
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very useful with JSON.stringifyand JSON.parse!
– charliebrownie
Feb 1 '16 at 13:31
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Using WebAPI or MVC to return JSON in ASP.NET
...ilding an ASP.NET MVC application that is client-script heavy, it will use JSON and jQuery to manipulate the DOM.
6 Answers...
How to set an “Accept:” header on Spring RestTemplate request?
...aders();
headers.setAccept(Collections.singletonList(MediaType.APPLICATION_JSON));
HttpEntity<String> entity = new HttpEntity<>("body", headers);
restTemplate.exchange(url, HttpMethod.POST, entity, String.class);
I prefer this solution because it's strongly typed, ie. exchange expect...
Sort JavaScript object by key
...ordered = {
'b': 'foo',
'c': 'bar',
'a': 'baz'
};
console.log(JSON.stringify(unordered));
// → '{"b":"foo","c":"bar","a":"baz"}'
const ordered = {};
Object.keys(unordered).sort().forEach(function(key) {
ordered[key] = unordered[key];
});
console.log(JSON.stringify(ordered)...