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Inline labels in Matplotlib
...e(np.int32)
# mask stuff outside plot
mask = (xy[:,0] >= 0) & (xy[:,0] < N) & (xy[:,1] >= 0) & (xy[:,1] < N)
xy = xy[mask]
# add to pop
for p in xy:
pop[l][tuple(p)] = 1.0
# find whitespace, nice place for label...
How can I check which version of Angular I'm using?
... itself.
Header of the current angular.js:
/**
* @license AngularJS v1.0.6
* (c) 2010-2012 Google, Inc. http://angularjs.org
* License: MIT
*/
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Using numpy to build an array of all combinations of two arrays
...
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How are the points in CSS specificity calculated
... algorithm is 256 or 28.
What this means is that a style specified with 0 ids and 256 class-names will over-ride a style specified with just 1 id. I tested this out with some fiddles:
255 classes are not enough to override 1 id
...but 256 classes are enough to override 1 id
...and 256 tag-name...
Are Javascript arrays sparse?
...
40
How exactly JavaScript arrays are implemented differs from browser to browser, but they generall...
Resolving MSB3247 - Found conflicts between different versions of the same dependent assembly
...he appropriate setting depending on your version:
Diagnostics when on VS2012, VS2013 or VS2015 (the message in these versions says you should use "Detailed", but this is plain wrong, you should use "Diagnostics")
Detailed when you're on VS2010
Normal will suffice in VS2008 or older.
Build the pro...
Find XOR of all numbers in a given range
...ven a large range [a,b] where 'a' and 'b' can be typically between 1 and 4,000,000,000 inclusive. You have to find out the XOR of all the numbers in the given range.
...
Disable/turn off inherited CSS3 transitions
..." class="transition">Content</a>
...and CSS:
a {
color: #f90;
-webkit-transition:color 0.8s ease-in, background-color 0.1s ease-in ;
-moz-transition:color 0.8s ease-in, background-color 0.1s ease-in;
-o-transition:color 0.8s ease-in, background-color 0.1s ease-in;
...
Mapping two integers to one, in a unique and deterministic way
...sy to define a bijection f : Z -> N, like so:
f(n) = n * 2 if n >= 0
f(n) = -n * 2 - 1 if n < 0
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Compare double to zero using epsilon
...there is a 52-bit mantissa and 11-bit exponent. Let's break it to bits:
1.0000 00000000 00000000 00000000 00000000 00000000 00000000 × 2^0 = 1
The smallest representable number greater than 1:
1.0000 00000000 00000000 00000000 00000000 00000000 00000001 × 2^0 = 1 + 2^-52
Therefore:
epsilon ...