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Getting the name of a variable as a string
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OK, finally got it! Installed using the following pip3 install python-varname==0.1.5; imported using from varname import nameof
– enter_display_name_here
Jun 6 at 2:42
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How do you read from stdin?
I'm trying to do some of the code golf challenges, but they all require the input to be taken from stdin . How do I get that in Python?
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What's the best way to inverse sort in scala?
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Both sortWith and sortBy have a compact syntax:
case class Foo(time:Long, str:String)
val l = List(Foo(1, "hi"), Foo(2, "a"), Foo(3, "X"))
l.sortWith(_.time > _.time) // List(Foo(3,X), Foo(2,a), Foo(1,hi))
l.sortBy(- _.time) // List(Foo(3,X), Foo(2,a), Foo(1,hi))
l....
Why does C++11 not support designated initializer lists as C99? [closed]
... named function arguments. But as of right now, name arguments don't officially exist. See N4172 Named arguments for a proposal of this. It would make code less error prone and easier to read.
– David Baird
Nov 29 '15 at 15:11
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C++ mark as deprecated
...erface that I want to deprecate with portable C++.
When I Googled for this all I got was a Microsoft specific solution; #pragma deprecated and __declspec(deprecated) .
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How do I best silence a warning about unused variables?
I have a cross platform application and in a few of my functions not all the values passed to functions are utilised. Hence I get a warning from GCC telling me that there are unused variables.
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Why is the order in dictionaries and sets arbitrary?
...der:
>>> {'bar': None, 'foo': None}
{'foo': None, 'bar': None}
All slots except 3 and 4 are empty, looping over the table first lists slot 3, then slot 4, so 'foo' is listed before 'bar'.
bar and baz, however, have hash values that are exactly 8 apart and thus map to the exact same slot...
What do *args and **kwargs mean? [duplicate]
...r **kwargs as the last items in your function definition’s argument list allows that function to accept an arbitrary number of arguments and/or keyword arguments.
For example, if you wanted to write a function that returned the sum of all its arguments, no matter how many you supply, you could wr...
How to run code when a class is subclassed? [duplicate]
...- Watcher subclasses type, not object. 2 - SuperClass has no superclass at all, not object. I'm just so used to writing down object as a superclass for every class I defined that I somehow missed it that this code was using something else. Although there doesn't seem to be any harm in making SuperCl...
Is it possible to print a variable's type in standard C++?
... return r;
}
The Results
With this solution I can do this:
int& foo_lref();
int&& foo_rref();
int foo_value();
int
main()
{
int i = 0;
const int ci = 0;
std::cout << "decltype(i) is " << type_name<decltype(i)>() << '\n';
std::cout << ...