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When should you use 'friend' in C++?

... Firstly (IMO) don't listen to people who say friend is not useful. It IS useful. In many situations you will have objects with data or functionality that are not intended to be publicly available. This is particularly true of large codebases with...
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How to output only captured groups with sed?

Is there any way to tell sed to output only captured groups? For example given the input: 8 Answers ...
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Formatting floats without trailing zeros

... share | improve this answer | follow | answered Mar 14 '10 at 1:11 Alex MartelliAlex Martell...
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Generate unique random numbers between 1 and 100

...te 8 unique random numbers and store them to an array, you can simply do this: var arr = []; while(arr.length < 8){ var r = Math.floor(Math.random() * 100) + 1; if(arr.indexOf(r) === -1) arr.push(r); } console.log(arr); ...
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What's the difference between lists and tuples?

... Apart from tuples being immutable there is also a semantic distinction that should guide their usage. Tuples are heterogeneous data structures (i.e., their entries have different meanings), while lists are homogeneous sequences. Tuples have structure, lists have or...
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Does Java SE 8 have Pairs or Tuples?

... UPDATE: This answer is in response to the original question, Does Java SE 8 have Pairs or Tuples? (And implicitly, if not, why not?) The OP has updated the question with a more complete example, but it seems like it can be solved witho...
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How do I check if an array includes a value in JavaScript?

What is the most concise and efficient way to find out if a JavaScript array contains a value? 54 Answers ...
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Haskell function composition (.) and function application ($) idioms: correct use

... I guess I can answer this from authority. Is there a reason for using the books way that is much better than using all ($) symbols? There's no special reason. Bryan and I both prefer to reduce line noise. . is quieter than $. As a result, the...
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Why does this iterative list-growing code give IndexError: list assignment index out of range?

... j is an empty list, but you're attempting to write to element [0] in the first iteration, which doesn't exist yet. Try the following instead, to add a new element to the end of the list: for l in i: j.append(l) Of cours...
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Why doesn't Ruby support i++ or i--​ (increment/decrement operators)?

... Here is how Matz(Yukihiro Matsumoto) explains it in an old thread: Hi, In message "[ruby-talk:02706] X++?" on 00/05/10, Aleksi Niemelä <aleksi.niemela@cinnober.com> writes: |I got an idea from http://www.pragprog.com...