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GetType() can lie?
...dFoo foo = new BadFoo();
Console.WriteLine("n1 and n2 are the same type: {0}",
Object.ReferenceEquals(n1.GetType(), foo.GetType()));
// output:
// n1 and n2 are the same type: True
so, yikes, you've successfully lied, right?
Well, yes and no... Consider that using this as an e...
How to wait for all goroutines to finish without using time.Sleep?
...xample.
– wobmene
Jun 29 '14 at 13:50
18
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Is GridFS fast and reliable enough for production?
...really fast (Core 2 duo 1.8Ghz) but the server has plenty storage space : 10Tb (sata) in raid 0 configuration. The job the server is doing is very simple:
Each product on our price-comparer has an image (there are around 10 million products according to our product db), and the servers job is to do...
How to get names of enum entries?
...og("enum member: ", enumMember);
}
Will print the following:
Enum member: 0
Enum member: 1
Enum member: bar
Enum member: foo
If you instead want only the member names, and not the values, you could do something like this:
for (var enumMember in myEnum) {
var isValueProperty = parseInt(enumMembe...
What's the difference between Protocol Buffers and Flatbuffers?
...rotobufs and FlatBuffers, here:
https://kentonv.github.io/capnproto/news/2014-06-17-capnproto-flatbuffers-sbe.html
However, the comparison focuses more on comparing the three new "zero-copy" serialization systems, and includes Protobufs mostly as a reference point. Also, I'm the author of Cap'n Pr...
Javascript Array Concat not working. Why?
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edited Oct 9 '12 at 15:40
Rocket Hazmat
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a...
How can I make a ComboBox non-editable in .NET?
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answered Sep 17 '08 at 17:38
Cory EngebretsonCory Engebretson
6,98544 gold badges1919 silver badges1717 bronze badges
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How to use mod operator in bash?
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Try the following:
for i in {1..600}; do echo wget http://example.com/search/link$(($i % 5)); done
The $(( )) syntax does an arithmetic evaluation of the contents.
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Autowiring two beans implementing same interface - how to set default bean to autowire?
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answered May 10 '12 at 12:35
skaffmanskaffman
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Accessing last x characters of a string in Bash
I found out that with ${string:0:3} one can access the first 3 characters of a string. Is there a equivalently easy method to access the last three characters?
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