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Meaning of acronym SSO in the context of std::string
... fixed at compile time, but the size of arrays from the free store is not. Moreover, the stack size is limited (typically a few MiB), whereas the free store is only limited by your system's memory.
SSO is the Short / Small String Optimization. A std::string typically stores the string as a pointer ...
Vim clear last search highlighting
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zsh compinit: insecure directories
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Exit single-user mode
...er id, filter by the database name. Post an image of the error to help us more. Good luck.
– CRAFTY DBA
Sep 23 '13 at 18:53
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Search code inside a Github project
...I, kept here for archive):
The search (based on SolrQuerySyntax) is now more permissive and the dreaded "Invalid search query. Try quoting it." is gone when using the default search selector "Everything":)
(I suppose we can all than Tim Pease, which had in one of his objectives "hacking on impro...
Why does modern Perl avoid UTF-8 by default?
...nally useful in some sort of rare and isolated case. Unicode is much much more than just a larger character repertoire; it’s also how those characters all interact in many, many ways.
Even the simple-minded minimal measures that (some) people seem to think they want are guaranteed to miserably b...
How to increment datetime by custom months in python without using library [duplicate]
... think for this instance add_months(date, 23), the year wouldn't increment more than 1. Anyway it solved my problem, perhaps it will solve others' such problems. Thanks a lot
– jargalan
Nov 9 '10 at 7:08
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How to show first commit by 'git log'?
...ced after this answer was posted.)
Explanation
Technically, there may be more than one root commit. This happens when multiple previously independent histories are merged together. It is common when a project is integrated via a subtree merge.
The git.git repository has six root commits in its hi...
What is the purpose of the var keyword and when should I use it (or omit it)?
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Django filter queryset __in for *every* item in list
... comments, to add .filter() for each category. Each additional filter adds more joins, which should not be a problem for small set of categories.
There is the aggregation approach. This query would be shorter and perhaps quicker for a large set of categories.
You also have the option of using cust...