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Index all *except* one item in python
... without the 3rd element:
a = range(10)[::-1] # [9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
b = [x for i,x in enumerate(a) if i!=3] # [9, 8, 7, 5, 4, 3, 2, 1, 0]
This is very general, and can be used with all iterables, including numpy arrays. If you replace [] with (), b will be an i...
Adjusting Eclipse console size
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0xCursor
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answered Apr 8 '10 at 14:29
MelMel
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How to sort a List alphabetically using Object name field
...compareTo(object2.getName());
}
});
}
Or if you are using Java 1.8
list
.stream()
.sorted((object1, object2) -> object1.getName().compareTo(object2.getName()));
One final comment -- there's no point in checking the list size. Sort will work on an empty list.
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Java integer to byte array
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298
using Java NIO's ByteBuffer is very simple:
byte[] bytes = ByteBuffer.allocate(4).putInt(169560...
How to encode the filename parameter of Content-Disposition header in HTTP?
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18 Answers
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Splitting a list into N parts of approximately equal length
...Testing:
>>> chunkIt(range(10), 3)
[[0, 1, 2], [3, 4, 5], [6, 7, 8, 9]]
>>> chunkIt(range(11), 3)
[[0, 1, 2], [3, 4, 5, 6], [7, 8, 9, 10]]
>>> chunkIt(range(12), 3)
[[0, 1, 2, 3], [4, 5, 6, 7], [8, 9, 10, 11]]
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django syncdb and an updated model
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answered Oct 22 '09 at 8:09
Dominic RodgerDominic Rodger
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What is database pooling?
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answered Oct 28 '10 at 8:39
paxdiablopaxdiablo
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How can you encode a string to Base64 in JavaScript?
..., so…
btoa() accepts a “string” where each character represents an 8-bit byte – if you pass a string containing characters that can’t be represented in 8 bits, it will probably break. This isn’t a problem if you’re actually treating the string as a byte array, but if you’re trying ...
How to check if all list items have the same value and return it, or return an “otherValue” if they
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answered Dec 8 '10 at 17:32
KeithSKeithS
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