大约有 47,000 项符合查询结果（耗时：0.0442秒） [XML]
Why #define TRUE (1==1) in a C boolean macro instead of simply as 1?
...) and actually use true and false.
In a C compiler, this is equivalent to 0 and 1.
(note that removing the parentheses will break that due to order of operations)
share
|
improve this answer
...
Zero-pad digits in string
I need to cast single figures (1 to 9) to (01 to 09). I can think of a way but its big and ugly and cumbersome. I'm sure there must be some concise way. Any Suggestions
...
How to convert an integer to a string in any base?
...tring.digits + string.ascii_letters
def int2base(x, base):
if x < 0:
sign = -1
elif x == 0:
return digs[0]
else:
sign = 1
x *= sign
digits = []
while x:
digits.append(digs[int(x % base)])
x = int(x / base)
if sign < 0:
...
Definition of a Balanced Tree
...|
edited Feb 5 '13 at 16:50
answered Feb 5 '13 at 16:30
com...
How do I add 1 day to an NSDate?
...
720
Swift 5.0 :
var dayComponent = DateComponents()
dayComponent.day = 1 // For removing...
Split a String into an array in Swift?
... like so:
var fullName = "First Last"
var fullNameArr = split(fullName) {$0 == " "}
var firstName: String = fullNameArr[0]
var lastName: String? = fullNameArr.count > 1 ? fullNameArr[1] : nil
with Swift 2
In Swift 2 the use of split becomes a bit more complicated due to the introduction of t...
List all indexes on ElasticSearch server?
...oncise list of all indices in your cluster, call
curl http://localhost:9200/_aliases
this will give you a list of indices and their aliases.
If you want it pretty-printed, add pretty=true:
curl http://localhost:9200/_aliases?pretty=true
The result will look something like this, if your indic...
C++: Rounding up to the nearest multiple of a number
...ger math.
int roundUp(int numToRound, int multiple)
{
if (multiple == 0)
return numToRound;
int remainder = numToRound % multiple;
if (remainder == 0)
return numToRound;
return numToRound + multiple - remainder;
}
Edit: Here's a version that works with negative n...
How should I validate an e-mail address?
...am", as will org.apache.commons.validator.routines.EmailValidator)
(?:[a-z0-9!#$%&'*+/=?^_`{|}~-]+(?:\.[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*|"(?:[\x01-\x08\x0b\x0c\x0e-\x1f\x21\x23-\x5b\x5d-\x7f]|\\[\x01-\x09\x0b\x0c\x0e-\x7f])*")@(?:(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+[a-z0-9](?:[a-z0-9-]*[a-z0...
Representing and solving a maze given an image
...
10 Answers
10
Active
...