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cv2.imshow command doesn't work properly in opencv-python
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check print img prints a correct numpy array, not a NoneType object.
– Abid Rahman K
Feb 17 '14 at 7:26
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How to increment a NSNumber
...ers represented as objects in Objective-C (i.e. if you need to put them in arrays, dictionaries, etc.) you should use NSDecimalNumber.
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Lists: Count vs Count() [duplicate]
... use a different type of collection (in that .Count() will work if it's an Array, a List, etc.)
– Don Cheadle
Jul 13 '16 at 18:35
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Printing the last column of a line in a file
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You don't need split() and an array, just save the last field and print that: awk '/A1/{f=$NF} END{print f}' file
– Ed Morton
Oct 24 '12 at 15:03
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Create and append dynamically
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var arrayDiv = new Array();
for(var i=0; i <= 1; i++){
arrayDiv[i] = document.createElement('div');
arrayDiv[i].id = 'block' + i;
arrayDiv[i].className = 'block' + i;
}
document.body.appendC...
Multi-gradient shapes
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p.setShape(new RectShape());
p.setShaderFactory(sf);
Basically, the int array allows you to select multiple color stops, and the following float array defines where those stops are positioned (from 0 to 1). You can then, as stated, just use this as a standard Drawable.
Edit: Here's how you could...
Get the first key name of a javascript object [duplicate]
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You can query the content of an object, per its array position.For instance:
let obj = {plainKey: 'plain value'};
let firstKey = Object.keys(obj)[0]; // "plainKey"
let firstValue = Object.values(obj)[0]; // "plain value"
/* or */
let [key, value] = Object.entries(...
Get the (last part of) current directory name in C#
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It's a params array, so .TrimEnd(Path.DirectorySeparatorChar, Path.AltDirectorySeparatorChar) works too.
– Kyle Delaney
Jul 16 '17 at 18:45
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How to force garbage collector to run?
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Say you had an array of weak references and wanted to check if any 'live' references existed. It would make sense to call GC.Collect() before checking. Just saying.
– Rich Ehmer
Apr 10 '14 at 15:10
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Any way to replace characters on Swift String?
...paration characters, you can use components() to break the string into and array, and then you can use the join() function to put them back to together with a specified separator.
let toArray = aString.components(separatedBy: " ")
let backToString = toArray.joined(separator: "+")
Or if you're loo...
