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In jQuery how can I set “top,left” properties of an element with position values relative to the par
.offset([coordinates]) method set the coordinates of an element but only relative to the document. Then how can I set coordinates of an element but relative to the parent?
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Why is lazy evaluation useful?
I have long been wondering why lazy evaluation is useful. I have yet to have anyone explain to me in a way that makes sense; mostly it ends up boiling down to "trust me".
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Multiprocessing: How to use Pool.map on a function defined in a class?
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I also was annoyed by restrictions on what sort of functions pool.map could accept. I wrote the following to circumvent this. It appears to work, even for recursive use of parmap.
from multiprocessing import Process, Pipe
from itertools imp...
No module named setuptools
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Install setuptools and try again.
try command:
sudo apt-get install -y python-setuptools
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Math - mapping numbers
How do I map numbers, linearly, between a and b to go between c and d.
9 Answers
9
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How do I sort a list of dictionaries by a value of the dictionary?
I have a list of dictionaries and want each item to be sorted by a specific property values.
18 Answers
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Get the position of a div/span tag
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This function will tell you the x,y position of the element relative to the page. Basically you have to loop up through all the element's parents and add their offsets together.
function getPos(el) {
// yay readability
for (var lx=0, ly=0;
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How to bind function arguments without binding this?
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You can do this, but best to avoid thinking of it as "binding" since that is the term used for setting the "this" value. Perhaps think of it as "wrapping" the arguments into a function?
What you do is create a function that...
Can pandas automatically recognize dates?
Today I was positively surprised by the fact that while reading data from a data file (for example) pandas is able to recognize types of values:
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How to join two JavaScript Objects, without using JQUERY [duplicate]
...ieve this:
1 - Native javascript for-in loop:
const result = {};
let key;
for (key in obj1) {
if(obj1.hasOwnProperty(key)){
result[key] = obj1[key];
}
}
for (key in obj2) {
if(obj2.hasOwnProperty(key)){
result[key] = obj2[key];
}
}
2 - Object.keys():
const result = {};
Obje...