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App Inventor 2 串口组件：App使用OTG数据线进行串口通信 · App Inventor 2 中文网
...可以看到，手机串口连接时，没有像PC那样指定“COM3”等端口，而是直接使用默认的USB设备：
切换 目录 关注 我们 关注我，不迷路 在线 ...
手机APP上的串口通信组件 - 创客硬件开发 - 清泛IT社区，为创新赋能！
...可以看到，手机串口连接时，没有像PC那样指定“COM3”等端口，而是直接使用默认的USB设备：
有一个英文原版视频，请参考“串口通信器“组件相关文档：《App Inventor 2 串口组件：App使用OTG数据线进行串口通信》
Error 507: unable to connect. is the device turned on? 无法连接，设备...
...rror-507-unable-to-connect/1474
BluetoothClient 组件仅支持支持串行端口配置文件 (SPP) 的设备。如果您的设备通过除 SPP UUID 之外的 UUID 支持 RFCOMM，则需要使用 ConnectWithUUID 块并指定设备所需的 UUID。
该方法采用两个参数。第一个是蓝牙...
App Inventor 2 MQTT拓展入门（保姆级教程） · App Inventor 2 中文网
...果如下：
App设计及代码
服务器地址：bemfa.com
端口：9501
客户端ID：（MQTT云控制台获取）
订阅主题：APPMQTT
新建项目，导入MQTT拓展，可在“界面设计”的拓展属性中进行服务器通信基本设置：
也可以在“程序设计...
MQTT接入EasyIoT平台 - 创客硬件开发 - 清泛IT社区，为创新赋能！
...。
新建一个订阅主题。
代码差别主要在：地址、端口不同，且使用用户名、密码认证（这里仅仅是演示，隐藏了部分，以实际为准），订阅主题使用上面新建的。
How well is Unicode supported in C++11?
...port is quite good, though: it supports detecting endianess from a BOM, or selecting it explicitly in code. It also supports producing output with and without a BOM.
There are some more interesting conversion possibilities absent. There is no way to deserialize from an UTF-16 byte stream or string ...
How do I redirect output to a variable in shell? [duplicate]
I have a script like that
8 Answers
8
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Request is not available in this context
...
Since there's no Request context in the pipeline during app start anymore, I can't imagine there's any way to guess what server/port the next actual request might come in on. You have to so it on Begin_Session.
Here's what I'm using when not in Classic Mode. The o...
SQL NVARCHAR and VARCHAR Limits
... large (unavoidable) dynamic SQL query. Due to the number of fields in the selection criteria the string containing the dynamic SQL is growing over 4000 chars. Now, I understand that there is a 4000 max set for NVARCHAR(MAX) , but looking at the executed SQL in Server Profiler for the statement
...
Generate random password string with requirements in javascript
...ough bits to "fill up" the full decimal space, the last digit will only be selected from a certain set of values. For example, on my computer, the last digit is only ever "i", "r", and "9". Use this instead: Math.random().toString(36).substr(2, 8)
– Joel
Jan 19...