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XDocument.ToString() drops XML Encoding Tag
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use this:
output.Text = String.Concat(xml.Declaration.ToString() , xml.ToString())
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How do I combine two data frames?
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You can also use pd.concat, which is particularly helpful when you are joining more than two dataframes:
bigdata = pd.concat([data1, data2], ignore_index=True, sort=False)
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Most efficient way to concatenate strings?
What's the most efficient way to concatenate strings?
17 Answers
17
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SQL: deleting tables with prefix
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In the MySQL shell or through PHPMyAdmin, use the following query
SELECT CONCAT( 'DROP TABLE ', GROUP_CONCAT(table_name) , ';' )
AS statement FROM information_schema.tables
WHERE table_name LIKE 'myprefix_%';
This will generate a DROP statement which you can than copy and execute to dr...
How to get the difference between two arrays of objects in JavaScript
...er(comparer(b));
var onlyInB = b.filter(comparer(a));
result = onlyInA.concat(onlyInB);
console.log(result);
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Calendar Recurring/Repeating Events - Best Storage Method
... EM1.`event_id` = EV.`id`
RIGHT JOIN `events_meta` EM2 ON EM2.`meta_key` = CONCAT( 'repeat_interval_', EM1.`id` )
WHERE EM1.meta_key = 'repeat_start'
AND (
( CASE ( 1299132000 - EM1.`meta_value` )
WHEN 0
THEN 1
ELSE ( 1299132000 - EM1.`meta_value` )
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How can I add an item to a IEnumerable collection?
...rovide all items of the old one, plus some of your own. You use Enumerable.Concat for that:
items = items.Concat(new[] { "foo" });
This will not change the array object (you cannot insert items into to arrays, anyway). But it will create a new object that will list all items in the array, and th...
String concatenation does not work in SQLite
...p>' from location;
From SQLite documentation:
The || operator is "concatenate" - it joins together the two strings of its operands.
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Shortcuts in Objective-C to concatenate NSStrings
Are there any shortcuts to ( stringByAppendingString: ) string concatenation in Objective-C, or shortcuts for working with NSString in general?
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How to add an object to an array
...of two arrays
var x = ['a', 'b', 'c'];
var y = ['d', 'e', 'f'];
var z = x.concat(y);
// x = ['a', 'b', 'c'] (remains unchanged)
// y = ['d', 'e', 'f'] (remains unchanged)
// z = ['a', 'b', 'c', 'd', 'e', 'f']
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