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What is the role of the bias in neural networks? [closed]
...g two dimensions to one dimension, as in reproducing the AND or the OR (or XOR) functions, you can think of a neuronal network as doing the following:
On the 2d plane mark all positions of input vectors. So, for boolean values, you’d want to mark (-1,-1), (1,1), (-1,1), (1,-1). What your ANN now ...
Why does GCC generate 15-20% faster code if I optimize for size instead of speed?
...53 push rbx
4004e7: 31 db xor ebx,ebx
4004e9: 41 8d 34 1c lea esi,[r12+rbx*1]
4004ed: 41 8d 7c 1d 00 lea edi,[r13+rbx*1+0x0]
4004f2: e8 db ff ff ff call 4004d2 <_ZL3addRKiS0_.isra.0&g...
ASP.NET Identity's default Password Hasher - How does it work and is it secure?
...lt;= secondHash.Length ? firstHash.Length : secondHash.Length;
var xor = firstHash.Length ^ secondHash.Length;
for (int i = 0; i < _minHashLength; i++)
xor |= firstHash[i] ^ secondHash[i];
return 0 == xor;
}
In in your custom ApplicationUserManager, you s...
Why do x86-64 instructions on 32-bit registers zero the upper part of the full 64-bit register?
...
Another related trick is to use XOR EAX, EAX because XOR RAX, RAX would need an REX prefix.
– Neil
Oct 2 '13 at 9:12
3
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BSS段、数据段、代码段、堆与栈 剖析 - C/C++ - 清泛网 - 专注C/C++及内核技术
..._run$[ebp+28], 8
mov DWORD PTR _run$[ebp+32], 9
mov ecx, 91 ; 0000005bH
xor eax, eax
lea edi, DWORD PTR _run$[ebp+36]
rep stosd
; Line 15
mov DWORD PTR _i$[ebp], 0
jmp SHORT $L534
$L535:
mov eax, DWORD PTR _i$[ebp]
add eax, 1
mov DWORD PTR _i$[ebp], eax
$L534:
cmp DWORD PTR _i$[ebp], 1...
Try-catch speeding up my code?
...ush esi
[0005] push ebx
[0006] sub esp,1Ch
[0009] xor eax,eax
[000b] mov dword ptr [ebp-20h],eax
[000e] mov dword ptr [ebp-1Ch],eax
[0011] mov dword ptr [ebp-18h],eax
[0014] mov dword ptr [ebp-14h],eax
[0017] xor eax,eax
...
What's the simplest way to test whether a number is a power of 2 in C++?
...he numbers is 0 0 0 0 = 0.
Time complexity : O(1).
Approach #3:
Bitwise XOR the number with its just previous number should be sum of both numbers.
Example: Number = 8
Binary of 8: 1 0 0 0
Binary of 7: 0 1 1 1 and the bitwise XOR of both the numbers is 1 1 1 1 = 15.
Time complexity : O(1).
htt...
Logic to test that 3 of 4 are True
...
Not sure it is simpler, but maybe.
((x xor y) and (a and b)) or ((x and y) and (a xor b))
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For i = 0, why is (i += i++) equal to 0?
...
Disassembly of the running code:
int i = 0;
xor edx, edx
mov dword ptr i, edx // set i = 0
i += i++;
mov eax, dword ptr i // set eax = i (=0)
mov dword ptr tempVar1, eax // set tempVar1 = eax (=0)
mov eax...
Easiest way to flip a boolean value?
...han longVariableName = !longVariableName; And every programmer should know XOR.
– xamid
Oct 5 '17 at 16:15
3
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