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dyld: Library not loaded … Reason: Image not found
...:
@executable_path/libboost_something.dylib (compatibility version 0.7.0, current version 0.7.0)
/usr/lib/libc++.1.dylib (compatibility version 1.0.0, current version 65.1.0)
/usr/lib/libSystem.B.dylib (compatibility version 1.0.0, current version 169.3.0)
and for each libb...
How to get different colored lines for different plots in a single figure?
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E.g.:
import matplotlib.pyplot as plt
import numpy as np
x = np.arange(10)
plt.plot(x, x)
plt.plot(x, 2 * x)
plt.plot(x, 3 * x)
plt.plot(x, 4 * x)
plt.show()
And, as you may already know, you can easily add a legend:
import matplotlib.pyplot as plt
import numpy as np
x = np.arange(10)
plt...
Which one will execute faster, if (flag==0) or if (0==flag)?
Interview question: Which one will execute faster, if (flag==0) or if (0==flag) ? Why?
16 Answers
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Selecting data frame rows based on partial string match in a column
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150
I notice that you mention a function %like% in your current approach. I don't know if that's a r...
Is it possible to declare two variables of different types in a for loop?
...tax has been supported in gcc and clang for years (since gcc-7 and clang-4.0) (clang live example). This allows us to unpack a tuple like so:
for (auto [i, f, s] = std::tuple{1, 1.0, std::string{"ab"}}; i < N; ++i, f += 1.5) {
// ...
}
The above will give you:
int i set to 1
double f set...
How to put the legend out of the plot
I have a series of 20 plots (not subplots) to be made in a single figure. I want the legend to be outside of the box. At the same time, I do not want to change the axes, as the size of the figure gets reduced. Kindly help me for the following queries:
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C char array initialization
... how you initialize an array, but for:
The first declaration:
char buf[10] = "";
is equivalent to
char buf[10] = {0, 0, 0, 0, 0, 0, 0, 0, 0, 0};
The second declaration:
char buf[10] = " ";
is equivalent to
char buf[10] = {' ', 0, 0, 0, 0, 0, 0, 0, 0, 0};
The third declaration:
char buf[...
RegEx to parse or validate Base64 data
...sion to match Base64 encoded words, you can use the following:
^(?:[A-Za-z0-9+/]{4})*(?:[A-Za-z0-9+/]{2}==|[A-Za-z0-9+/]{3}=)?$
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Is it worth using Python's re.compile?
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I've had a lot of experience running a compiled regex 1000s of times versus compiling on-the-fly, and have not noticed any perceivable difference. Obviously, this is anecdotal, and certainly not a great argument against compiling, but I've found the difference to be negligible.
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Flatten nested dictionaries, compressing keys
...t(items)
>>> flatten({'a': 1, 'c': {'a': 2, 'b': {'x': 5, 'y' : 10}}, 'd': [1, 2, 3]})
{'a': 1, 'c_a': 2, 'c_b_x': 5, 'd': [1, 2, 3], 'c_b_y': 10}
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