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MFC MDI切换menu原理 - C/C++ - 清泛网 - 专注C/C++及内核技术
...程序向导生成的SDI或MDI应用程序时，它创建了菜单资源（使用IDR_MAINFRAME作为其资源id。此菜单显示在所有时间SDI应用程序，并且仅在...当应用程序向导生成的 SDI 或 MDI 应用程序时，它创建了菜单资源 （使用 IDR_MAINFRAME 作为其资...
iOS UI系列 (二) ：使用多个StoryBoard - 更多技术 - 清泛网 - 专注C/C++及内核技术
iOS UI系列 (二) ：使用多个StoryBoard为什么要使用多个StoryBoardStoryBoard 给项目带了很大的方便，在一个视图里可以看到整个项目页面之间的关系，但是如果项目所有的页面都放...为什么要使用多个StoryBoard
StoryBoard 给项目带了很大...
App Inventor 2 如何接入ChatGPT：国内访问OpenAI的最佳方式 · App Inventor 2 中文网
...（被屏蔽）以外才行。因此对于大多数人来说，想体验或使用ChatGPT就不太便利，不过App Inventor 2 为我们提供了相对便利的一种方式，即“试验性质”下的“ChatBot”及“ImageBot”组件（要求AI伴侣版本 >= v2.67）：
都是调用ChatGPT...
How to create index on JSON field in Postgres?
In PostgreSQL 9.3 Beta 2 (?), how do I create an index on a JSON field? I tried it using the -> operator used for hstore but got the following error:
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Ajax success event not working
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The result is probably not in JSON format, so when jQuery tries to parse it as such, it fails. You can catch the error with error: callback function.
You don't seem to need JSON in that function anyways, so you can also take out the dataType: 'json' row....
Ignore fields from Java object dynamically while sending as JSON from Spring MVC
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Add the @JsonIgnoreProperties("fieldname") annotation to your POJO.
Or you can use @JsonIgnore before the name of the field you want to ignore while deserializing JSON. Example:
@JsonIgnore
@JsonProperty(value = "user_password")
pu...
Error handling in getJSON calls
How can you handle errors in a getJSON call? Im trying to reference a cross-domain script service using jsonp, how do you register an error method?
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In Node.js, how do I turn a string to a json? [duplicate]
For example, a HTTP REST API just returned me a JSON, but of course it's a string right now. How can I turn it into a JSON?
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How to copy JavaScript object to new variable NOT by reference? [duplicate]
I wrote a quick jsfiddle here , where I pass a small JSON object to a new variable and modify the data from the original variable (not the new variable), but the new variable's data gets updated as well. This must mean that the JSON object was passed by reference, right?
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JavaScript data formatting/pretty printer
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One short coming of this approach (compared with the JSON.stringify method Jason suggests) is that it does not show arrays of objects properly. When you have an array of objects it shows up as [object Object].
– Ryan
Mar 12 '10 at 17:58
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