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What do 'real', 'user' and 'sys' mean in the output of time(1)?
...used. Note that this is across all CPUs, so if the process has multiple threads (and this process is running on a computer with more than one processor) it could potentially exceed the wall clock time reported by Real (which usually occurs). Note that in the output these figures include the User a...
Sorting rows in a data table
... Great minds think alike. I was about to post the same solution after reading @JayR's.
– Drew Chapin
Jun 14 '17 at 21:59
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How to specify HTTP error code?
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For anyone reading this in 2016: As per Express 4.x, res.send(404) is deprecated. It's now res.sendStatus(404). expressjs.com/en/api.html#res.sendStatus
– 0xRm
Jun 28 '16 at 6:35
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jQuery 1.9 .live() is not a function
... migration guide below. You must not simply replace .live() with .on()!
Read before you start doing a search and replace:
For quick/hot fixes on a live site, do not just replace the keyword live with on, as the parameters are different!
.live(events, function)
should map to:
.on(eventType, s...
npm WARN package.json: No repository field
...{
"type": "git",
"url": "git://github.com/username/repository.git"
}
Read more about the repository field, and see the logged bug for further details.
Additionally, as originally reported by @dan_nl, you can set private key in your package.json.
This will not only stop you from accidentally...
Getting user input [duplicate]
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@wizzwizz4 it absolutely does. Did you read what I put?
– Kyle Falconer
Jun 8 '16 at 13:53
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Check whether a cell contains a substring
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Welcome to SO. You should read up on what makes a good answer.
– geotheory
Mar 23 '16 at 13:41
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Convert HashBytes to VarChar
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Where can I read about these convert styles? 2 in this case which is passed as the parameter. And how to make an equivalent of that in C# code? What encoding should I choose?
– Dmytro Zhluktenko
Oct...
Why does Javascript's regex.exec() not always return the same value? [duplicate]
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In case anyone has read this far, here's a fiddle to further explain my plight (which is explained by @squint's answer above): jsfiddle.net/grammar/k2hxsq8d/2
– grammar
Jul 27 '15 at 19:57
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One line if statement not working
...if is an expression. In fact, everything is an expression in Ruby, so it already can return a value. There is no need for the conditional operator to even exist, let alone use it.
BTW: it is customary to name methods which are used to ask a question with a question mark at the end, like this:
@ite...