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How do I get the name of the active user via the command line in OS X?

How do I get the name of the active user via the command line in OS X? 12 Answers 12 ...
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What's a good Java, curses-like, library for terminal applications? [closed]

...e, too bad though that it requires native libraries. I'll give this a shot and see how far I get. – Francisco Canedo Jan 16 '09 at 12:03 24 ...
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How do I use a Boolean in Python?

... Actually Python didn't have a boolean type for a long time (as in old C), and some programmers still use integers instead of booleans. share | improve this answer | follow ...
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Create instance of generic type whose constructor requires a parameter?

... will need to ensure yourself regarding the specific constructor existing, and this kind of requirement may be a code smell (or rather something you should just try to avoid in the current version on c#). share | ...
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Select data from date range between two dates

I have a table Named Product_Sales and it holds data like this 19 Answers 19 ...
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Return anonymous type results?

...}; return result; } It means you have an extra class, but it's quick and easy to code, easily extensible, reusable and type-safe. share | improve this answer | follow ...
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Persist javascript variables across pages? [duplicate]

...window.someVar = 5 . Then I move to Page B, via clicking a hyperlink in A, and do something like alert(window.someVar) -- I should get a message box displaying 5. Is there a technique to persist someVar as such...? ...
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Print only?

... this is by far the fastest and cleanest way, i wonder why this answer didn't get the most votes -.- – Dany Khalife Nov 6 '11 at 21:14 ...
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Python debugging tips [closed]

... PDB You can use the pdb module, insert pdb.set_trace() anywhere and it will function as a breakpoint. >>> import pdb >>> a="a string" >>> pdb.set_trace() --Return-- > <stdin>(1)<module>()->None (Pdb) p a 'a string' (Pdb) To continue executio...
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Can two different strings generate the same MD5 hash code?

... For a set of even billions of assets, the chances of random collisions are negligibly small -- nothing that you should worry about. Considering the birthday paradox, given a set of 2^64 (or 18,446,744,073,709,551,616) assets, the probability of a single MD5 collision within this...