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Linear Regression and group by in R
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fits <- lmList(response ~ year | state, data=d)
fits
#------------
Call: lmList(formula = response ~ year | state, data = d)
Coefficients:
(Intercept) year
CA -1.34420990 0.17139963
NY 0.00196176 -0.01852429
Degrees of freedom: 20 total; 16 residual
Residual standard error: 0.820...
TortoiseSVN icons not showing up under Windows 7
I can't seem to get the icons to display under Windows 7 and I really miss this from Windows XP.
31 Answers
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Is there a builtin identity function in python?
...hink about the signature and time costs.
So a better way to do it is actually (a lambda avoids naming the function):
_ = lambda *args: args
advantage: takes any number of parameters
disadvantage: the result is a boxed version of the parameters
OR
_ = lambda x: x
advantage: doesn't change...
Annotating text on individual facet in ggplot2
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Typically you'd do something like this:
ann_text <- data.frame(mpg = 15,wt = 5,lab = "Text",
cyl = factor(8,levels = c("4","6","8")))
p + geom_text(data = ann_text,label = "Text")
It should work without specifying the factor variable comple...
Converting numpy dtypes to native python types
If I have a numpy dtype, how do I automatically convert it to its closest python data type? For example,
12 Answers
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Android View.getDrawingCache returns null, only null
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sorry, personally, can't help you with your question :'( -> nice that it worked :)
– cV2
Jul 26 '13 at 11:36
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How useful/important is REST HATEOAS ( maturity level 3)?
... members believe that a REST API has to be HATEOAS compliant and implement all Richardson's maturity levels ( http://martinfowler.com/articles/richardsonMaturityModel.html )!
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Registry Key '…' has value '1.7', but '1.6' is required. Java 1.7 is Installed and the Registry is P
... one of the server admins "updated" our Java to an older version and uninstalled the one we were using. Don't ask me why, I don't know. I re-installed Java 1.7 and uninstalled 1.6 along with the JREs.
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Get controller and action name from within controller?
...outeValues["id"];
else if (HttpContext.Current.Request.QueryString.AllKeys.Contains("id"))
return HttpContext.Current.Request.QueryString["id"];
return string.Empty;
}
public static string Controller(this HtmlHelper htmlHelper)
{
var routeValues = Ht...
sort object properties and JSON.stringify
...Obj, Object.keys(flattenObject(sortMyObj)).sort());
To do it programmatically with something you can tweak yourself, you need to push the object property names into an array, then sort the array alphabetically and iterate through that array (which will be in the right order) and select each value ...