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Java recursive Fibonacci sequence
...(4) = fibonacci(3) + fibonacci(2)
fibonacci(2) = fibonacci(1) + fibonacci(0)
Now you already know fibonacci(1)==1 and fibonacci(0) == 0. So, you can subsequently calculate the other values.
Now,
fibonacci(2) = 1+0 = 1
fibonacci(3) = 1+1 = 2
fibonacci(4) = 2+1 = 3
fibonacci(5) = 3+2 = 5
And fr...
Getting key with maximum value in dictionary?
...
You can use operator.itemgetter for that:
import operator
stats = {'a':1000, 'b':3000, 'c': 100}
max(stats.iteritems(), key=operator.itemgetter(1))[0]
And instead of building a new list in memory use stats.iteritems(). The key parameter to the max() function is a function that computes a key th...
List comprehension in Ruby
...1, 2, 3, 4, 5, 6]
new_array = some_array.comprehend {|x| x * 3 if x % 2 == 0}
puts new_array
Prints:
6
12
18
I would probably just do it the way you did though.
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Position of least significant bit that is set
... position of the least significant bit that is set in an integer, e.g. for 0x0FF0 it would be 4.
22 Answers
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How do I truncate a .NET string?
...lue;
return value.Length <= maxLength ? value : value.Substring(0, maxLength);
}
}
Now we can write:
var someString = "...";
someString = someString.Truncate(2);
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How to convert a boolean array to an int array
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answered Jul 6 '13 at 19:10
BrenBarnBrenBarn
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How do I check if there are duplicates in a flat list?
...
406
Use set() to remove duplicates if all values are hashable:
>>> your_list = ['one', 't...
How does the socket API accept() function work?
...s going.
Example to clarify things:
Say we have a server at 192.168.1.1:80 and two clients, 10.0.0.1 and 10.0.0.2.
10.0.0.1 opens a connection on local port 1234 and connects to the server. Now the server has one socket identified as follows:
10.0.0.1:1234 - 192.168.1.1:80
Now 10.0.0.2 open...
What optimizations can GHC be expected to perform reliably?
...
+150
This GHC Trac page also explains the passes fairly well. This page explains the optimization ordering, though, like the majority of th...
How can I obtain the element-wise logical NOT of a pandas Series?
...~s:
In [7]: s = pd.Series([True, True, False, True])
In [8]: ~s
Out[8]:
0 False
1 False
2 True
3 False
dtype: bool
Using Python2.7, NumPy 1.8.0, Pandas 0.13.1:
In [119]: s = pd.Series([True, True, False, True]*10000)
In [10]: %timeit np.invert(s)
10000 loops, best of 3: 91.8 µs...