大约有 11,291 项符合查询结果(耗时:0.0220秒) [XML]

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What's the algorithm to calculate aspect ratio?

... I gather you're looking for an usable aspect ratio integer:integer solution like 16:9 rather than a float:1 solution like 1.77778:1. If so, what you need to do is find the greatest common divisor (GCD) and divide both values by that. The GCD is the highest n...
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Do the parentheses after the type name make a difference with new?

If 'Test' is an ordinary class, is there any difference between: 6 Answers 6 ...
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Why are elementwise additions much faster in separate loops than in a combined loop?

Suppose a1 , b1 , c1 , and d1 point to heap memory and my numerical code has the following core loop. 10 Answers ...
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Sample random rows in dataframe

...ruggling to find the appropriate function that would return a specified number of rows picked up randomly without replacement from a data frame in R language? Can anyone help me out? ...
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Listing all permutations of a string/integer

...f interviews though) is to take a string or an integer and list every possible permutation. 28 Answers ...
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Return anonymous type results?

Using the simple example below, what is the best way to return results from multiple tables using Linq to SQL? 16 Answers ...
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Fast way of counting non-zero bits in positive integer

I need a fast way to count the number of bits in an integer in python. My current solution is 9 Answers ...
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SQL JOIN vs IN performance?

...g a JOIN or an IN will give me the correct results... Which typically has better performance and why? How much does it depend on what database server you are running? (FYI I am using MSSQL) ...
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Simultaneously merge multiple data.frames in a list

...o merge. The issue here is that each data.frame differs in terms of the number of rows and columns, but they all share the key variables (which I've called "var1" and "var2" in the code below). If the data.frames were identical in terms of columns, I could merely rbind , for which plyr's rbind...
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count the frequency that a value occurs in a dataframe column

... Use groupby and count: In [37]: df = pd.DataFrame({'a':list('abssbab')}) df.groupby('a').count() Out[37]: a a a 2 b 3 s 2 [3 rows x 1 columns] See the online docs: http://pandas.pydata.org/pandas-docs/stable/groupby.htm...