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QRCodeGenerator 拓展使用后,apk编译失败 - 用户反馈 - 清泛IT社区,为创新赋能!
...ing库,解决apk编译问题。
拓展开发中。。
https://www.fun123.cn/reference/ ... RCodeGenerator.html
原版来自:
https://community.appinventor.mi ... -extension/47908/34
自研版已上线,编译apk正常:https://www.fun123.cn/reference/extensions/QRCodeGenerator.html
ImagePicker 图像选择器如何一次选择多张图片? - App Inventor 2 中文网 -...
https://www.fun123.cn/reference/components/media.html#ImagePicker
根据文档最新版本,是可以选多张图片的,但是实际测试下来,一次只能选一张,可能跟安卓版本及手机有关,可能有的手机可以选择多张,纯猜测未验证。英文社区也有相关...
App Inventor接入Supabase:开源免费的后端新选择 - App Inventor 2 拓展 -...
...客户端)
4. 安装Supabase扩展
在 App Inventor中文网(fun123.cn) 下载Supabase扩展组件,导入到项目中。
5. 配置连接
将Supabase URL和API Key填入扩展组件的对应属性中,即可开始使用。
注意事项
关于匿名登录:Supabase默认没...
App Inventor 2 鸿蒙先行版:AppInventor 从此支持全平台,不再安卓专属 - ...
大家好,这里是 App Inventor 2 中文网(fun123.cn)。
今天想和大家聊一个很多人关心、但我们一直比较谨慎的话题——App Inventor 2 的鸿蒙(HarmonyOS NEXT)版本。
————————————————
先说结论
鸿蒙先行版已...
TypeError: ObjectId('') is not JSON serializable
...
123
You should define you own JSONEncoder and using it:
import json
from bson import ObjectId
cl...
Pretty-Print JSON in Java
...1111") // "number":"555-1111",
.write("extension", "123") // "extension":"123"
.writeEnd() // },
.writeStartObject() // {
.write("number", "555-2222") // "number":"555-2222",
...
Format Float to n decimal places
...ed the result is a float number, not a string.
– seba123neo
Mar 4 '11 at 18:29
Are you saying you want to round the fl...
Ordering by the order of values in a SQL IN() clause
...
Two solutions that spring to mind:
order by case id when 123 then 1 when 456 then 2 else null end asc
order by instr(','||id||',',',123,456,') asc
(instr() is from Oracle; maybe you have locate() or charindex() or something like that)
...
What to use as an initial version? [closed]
...ackage.json will behave different. docs.npmjs.com/misc/semver#caret-ranges-123-025-004 You can use 0.x instead of ^0. in package json for this scenario. Therefore, 1.x is a bit more easy to start and use.
– Sam
Mar 30 at 11:23
...
Convert columns to string in Pandas
...der,
# Setup
df = pd.DataFrame({'A': ['a', 'b', 'c'], 'B': [{}, [1, 2, 3], 123]})
df
A B
0 a {}
1 b [1, 2, 3]
2 c 123
Upto pandas 0.25, there was virtually no way to distinguish that "A" and "B" do not have the same type of data.
# pandas <= 0.25
df.dtypes
A ...
