大约有 40,000 项符合查询结果（耗时：0.0494秒） [XML]
Encoding an image file with base64
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How to find the size of localStorage
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Depends on the character set (i.e. utf8, etc) which that doesn't account for
– jas-
Sep 24 '14 at 11:18
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Difference between two lists
... need duplicates to be preserved, it would probably be easiest to create a set from list2 and use something like:
var list3 = list1.Where(x => !set2.Contains(x)).ToList();
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JSON formatter in C#?
Looking for a function that will take a string of Json as input and format it with line breaks and indentations. Validation would be a bonus, but isn't necessary, and I don't need to parse it into an object or anything.
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Sanitizing strings to make them URL and filename safe?
... * $force_lowercase - Force the string to lowercase?
* $anal - If set to *true*, will remove all non-alphanumeric characters.
*/
function sanitize($string, $force_lowercase = true, $anal = false) {
$strip = array("~", "`", "!", "@", "#", "$", "%", "^", "&", "*", "(", ")", "_", "=",...
Remove final character from string [duplicate]
Let's say my string is 10 characters long.
2 Answers
2
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ifstream 线程安全读文件 - C/C++ - 清泛网 - 专注C/C++及内核技术
ifstream 线程安全读文件函数 safeGetline：std::istream& safeGetline(std::istream& is, std::string& t){ t clear(); 使用std::streambuf 函数 safeGetline：
std::istream& safeGetline(std::istream& is, std::string& t)
{
t.clear();
//这比使用std::istream逐个读...
What are the details of “Objective-C Literals” mentioned in the Xcode 4.4 release notes?
...ng>)key {
id oldObject = [_storage objectForKey:key];
[_storage setObject:object forKey:key];
return oldObject;
}
@implementation Database {
NSMutableDictionary *_storage;
}
- (id)replaceObject:(id)newObject forKey:(id <NSCopying>)key {
id oldObject = _storage[key];...
C: differences between char pointer and array [duplicate]
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@zen: Setting pmessage to point to another string will have absolutely no effect on the contents of the string literal stored at 0x0000800. The storage for that string literal won't be released until the program exits.
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Transpose list of lists
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How about
map(list, zip(*l))
--> [[1, 4, 7], [2, 5, 8], [3, 6, 9]]
For python 3.x users can use
list(map(list, zip(*l)))
Explanation:
There are two things we need to know to understand what's going on:
The signature of zip: zip(*iterables) This means zip expects an arbitrary number of ...